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4 years ago

What’s a triangle no

Mathematics

1 answer:

loris [4]4 years ago

3 0

Answer:

a plane figure with three straight sides and three angles.

Step-by-step explanation:

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A quantity with an initial value of 600 decays exponentially at a rate of

Snowcat [4.5K]

Answer:

The value of the quantity after 87 months will be of 599.64.

Step-by-step explanation:

A quantity with an initial value of 600 decays exponentially at a rate of 0.05% every 6 years.

This means that the quantity, after t periods of 6 years, is given by:

$Q(t) = 600(1 - 0.0005)^{t}$

What is the value of the quantity after 87 months, to the nearest hundredth?

6 years = 6*12 = 72 months

So 87 months is 87/72 = 1.2083 periods of 6 years. So we have to find Q(1.2083).

$Q(t) = 600(1 - 0.0005)^{t}$

$Q(1.2083) = 600(1 - 0.0005)^{1.2083} = 599.64$

The value of the quantity after 87 months will be of 599.64.

8 0

3 years ago

Find the value of x: 7e(×/3)=14

velikii [3]

7e^(×/3)=14
e^(×/3)=14/7
e^(×/3)=2
take ln of both sides;
lne^(×/3)=ln2
****You should be familiar that lne^x=x as ln is the inverse function of e and vice versa****
then;
x/3=ln2
x=3ln2
x approximately is equal to 2.1

6 0

3 years ago

−8−1+4 ⋅ 2 find the answer to this equation

jeyben [28]

Answer:

-1

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What is the equation of the line perpendicular to 3x+y= -8that passes through -3,1? Write your answer in slope-intercept form. S

Gekata [30.6K]

Slope intercept form of a line perpendicular to 3x + y = -8, and passing through (-3,1) is $y=\frac{1}{3} x+2$

Solution:

Need to write equation of line perpendicular to 3x+y = -8 and passes through the point (-3,1).

Generic slope intercept form of a line is given by y = mx + c

where m = slope of the line.

Let's first find slope intercept form of 3x + y = -8

3x + y = -8

=> y = -3x - 8

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c , we can say that for line 3x + y = -8 , slope m = -3

And as the line passing through (-3,1) and is perpendicular to 3x + y = -8, product of slopes of two line will be -1 as lies are perpendicular.

Let required slope = x

$\begin{array}{l}{=x \times-3=-1} \\\\ {=>x=\frac{-1}{-3}=\frac{1}{3}}\end{array}$

So we need to find the equation of a line whose slope is $\frac{1}{3}$ and passing through (-3,1)

Equation of line passing through $(x_1 , y_1)$ and having lope of m is given by

$\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)$

$\text { In our case } x_{1}=-3 \text { and } y_{1}=1 \text { and } \mathrm{m}=\frac{1}{3}$

Substituting the values we get,

$\begin{array}{l}{(\mathrm{y}-1)=\frac{1}{3}(\mathrm{x}-(-3))} \\\\ {=>\mathrm{y}-1=\frac{1}{3} \mathrm{x}+1} \\\\ {=>\mathrm{y}=\frac{1}{3} \mathrm{x}+2}\end{array}$

Hence the required equation of line is found using slope intercept form

4 0

3 years ago

Sora was given two data sets, one without an outlier and one with an outlier. Data without an outlier: 108, 113, 105, 118, 124,

gladu [14]

The outlier (61) is at the low end of the data set, but doesn't affect the mean by a lot, so ...

The mean is centered among the other numbers in both sets of data.

_____

The mean without the outlier is 114. With the outlier, it is 107.4. The lower quartile is 108, so the mean does get moved outside the "box" of the box-and-whisker plot of the data set without the outlier.

8 0

3 years ago

Read 2 more answers