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3 years ago

454.12kg ;3 significant digits

Mathematics

1 answer:

Westkost [7]3 years ago

4 0

You can write it as 454 kg in 3 significant digits.

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The National Association of College and University Business Officers collects data on college endowments. In 2015, its report in

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Step-by-step explanation:

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3 years ago

Select the correct answer.

katen-ka-za [31]

Answer:

3x - 4/2

Step-by-step explanation:

2 result(s) for "f(x) = 4x³ - 10 g(x)

6 0

2 years ago

Write an equation for the nth term of the geometric sequences. Then Find a6

love history [14]

Answer: The nth term of a geometric progression is Tn = ar^(n-1)

A. 12

B. 3.6

C. -3/4

D. 0.6

Step-by-step explanation:

The nth term of a geometric progression is Tn = ar^(n-1)

Where Tn= nth term

a = first term

r = common ratio

n = number

A. a6 = (2*6) = 12

B. a6 = (0.6*6) = 3.6

C. a6 = (-1/8*6) = -3/4

D. a6 = (0.1*6) = 0.6

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3 years ago

150 students were surveyed to see what sport they play what percentage plays soccer

Anna35 [415]

Not enough info.
You need to know how many played soccer.

If the number who played soccer is represented by S;

Then percentage = S/150 x 100

7 0

3 years ago

Circles are described below by the coordinates of their centers, C, and one point on their circumference, A. Determine an equati

Art [367]

Using the given center and point at the circumference, the equation of the circles are:

a) $(x - 5)^2 + (y - 2)^2 = 100$

b) $(x + 2)^2 + (y + 5)^2 = 169$

c) $(x - 5)^2 + (y + 1)^2 = 65$

<h3>What is the equation of a circle?</h3>

The equation of a circle of radius r and center $(x_0,y_0)$ is given by:

$(x - x_0)^2 + (y - y_0)^2 = r^2$

Item a:

Center C(5,2), hence $x_0 = 5, y_0 = 2$ .

The point at the circumference is A(11,10), hence:

$(x - 5)^2 + (y - 2)^2 = r^2$

$(11 - 5)^2 + (10 - 2)^2 = r^2$

$r^2 = 100$

Hence:

$(x - 5)^2 + (y - 2)^2 = 100$

Item b:

Center C(-2,-5), hence $x_0 = -2, y_0 = -5$ .

The point at the circumference is A(3,-17), hence:

$(x + 2)^2 + (y + 5)^2 = r^2$

$(3 + 2)^2 + (-17 - 5)^2 = r^2$

$r^2 = 169$

Hence:

$(x + 2)^2 + (y + 5)^2 = 169$

Item c:

Center C(5,-1), hence $x_0 = 5, y_0 = -1$ .

The point at the circumference is A(-2,-5), hence:

$(x - 5)^2 + (y + 1)^2 = r^2$

$(-2 - 5)^2 + (-5 + 1)^2 = r^2$

$r^2 = 65$

Hence:

$(x - 5)^2 + (y + 1)^2 = 65$

You can learn more about equation of a circle at brainly.com/question/24307696

4 0

2 years ago