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Alexxandr [17]
3 years ago
11

Camila sets up a passcode on her tablet, which allows only nine-digit codes. A spy sneaks a look at Camila's tablet and sees her

fingerprints on the screen over nine numbers. What is the probability the spy is able to unlock the tablet on his first try
Mathematics
1 answer:
laila [671]3 years ago
7 0

Answer:

\frac{1}{10^9} probability the spy is able to unlock the tablet on his first try.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Desired outcomes:

1 correct password, so D = 1

Total outcomes:

Nine-digit codes.

For each digit, there are 10 possible outcomes. So

T = 10^9

What is the probability the spy is able to unlock the tablet on his first try?

p = \frac{D}{T} = \frac{1}{10^9}

\frac{1}{10^9} probability the spy is able to unlock the tablet on his first try.

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Divide to find equivalent fractions 40/100=10/10
Aleks04 [339]

Answer:

4/10=1

Step-by-step explanation:

Divide both fractions by 10 and you get 4/10=1

6 0
3 years ago
Deisha can build a fence in 15 hours, and Travis can build a fence in 12 hours. How long will it take them together to build a f
Basile [38]

Answer:

6\frac{2}{3}

Step-by-step explanation:

Deisha's build rate = 1 fence per 15 hours = 1/15 fences per hour

Travis's build rate = 1 fence per 12 hours = 1/12 fences per hour

Working together, their combined rate is 1/15 + 1/12 = 3/20 fences per hour

So it takes them 20/3 = 6 2/3 hours per fence

6 0
3 years ago
Three-fifths of the sum of 9 and f
blsea [12.9K]

Answer:  \frac{3}{5} f+\frac{27}{5}

Step-by-step explanation:

Three-fifths of the sum of 9 and f is \frac{3}{5} (9+f)=\frac{27}{5} +\frac{3}{5} f=\frac{3}{5} f+\frac{27}{5}

7 0
3 years ago
A quality control specialist at a pencil manufacturer pulls a random sample of 45 pencils from the assembly line. The pencils ha
amm1812

Answer:

The P-value you would use to test the claim that the population mean of  pencils produced in that factory have a mean length equal to 18.0 cm is 0.00736.

Step-by-step explanation:

We are given that a quality control specialist at a pencil manufacturer pulls a random sample of 45 pencils from the assembly line.

The pencils have a mean length of  17.9 cm. Given that the population standard deviation is 0.25 cm.

Let \mu = <u><em>population mean length of  pencils produced in that factory.</em></u>

So, Null Hypothesis, H_0 : \mu = 18.0 cm     {means that the population mean of  pencils produced in that factory have a mean length equal to 18.0 cm}

Alternate Hypothesis, H_A : \mu\neq 18.0 cm     {means that the population mean of  pencils produced in that factory have a mean length different from 18.0 cm}

The test statistics that will be used here is <u>One-sample z-test</u> statistics because we know about the population standard deviation;

                           T.S.  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean length of pencils = 17.9 cm

           \sigma = population standard deviation = 0.25 cm

           n = sample of pencils = 45

So, <u><em>the test statistics</em></u> =  \frac{17.9-18.0}{\frac{0.25}{\sqrt{45} } }  

                                    =  -2.68

The value of z-test statistics is -2.68.

<u>Now, the P-value of the test statistics is given by;</u>

         P-value = P(Z < -2.68) = 1 - P(Z \leq 2.68)

                      = 1- 0.99632 = 0.00368

For the two-tailed test, the P-value is calculated as = 2 \times 0.00368 = 0.00736.

7 0
3 years ago
1234
Yuki888 [10]
150mm. Is your answer
8 0
3 years ago
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