All categories

3 years ago

What is12.869 x 5.847?.z

Mathematics

1 answer:

kotegsom [21]3 years ago

7 0

Answer:

75.245 or 75.25

Step-by-step explanation:

You might be interested in

Swati is substituting t=5 and t=9 to determine if the two expressions are equivalent.

horrorfan [7]

Answer:

No the two expressions are not equivalent.

Step-by-step explanation:

the given two expressions t=5 and t=9 are not equivalent because t being a variable cant take two numbers at a same time.however if they are placed in given two expressions of 't' such that that they give equal value when the first expression gives a value 'a' at t=5 while the other expression gives a value 'a' at t=9 then those two expressions will be equal.

4 0

3 years ago

Read 2 more answers

When asked to rewrite the expression (x3 + 2x? – x)-(-x3 + 2x2 + 6), Denise made a mistake. She did not get the correct answer,

DanielleElmas [232]

Answer:

She rewrote the problem without parentheses: x3+ 2x2 - x + x3 – 2x2 +6

Step-by-step explanation:

It looks like she didn't fully distribute the -

(x3 + 2x2 - x)-(-x3 + 2x2 + 6) :Original

x3+ 2x2 - x + x3 – 2x2 +6 :Changed

(x3 + 2x2 - x)-(-x3 + 2x2 + 6)

x3 + 2x2 - x + x3 - 2x2 - 6

x3 + x3 + 2x2 - 2x2 -x - 6

2x3-x-6

I hope this helps ^-^

3 0

2 years ago

For what values of <img src="https://tex.z-dn.net/?f=x" id="TexFormula1" title="x" alt="x" align="absmiddle" class="latex-formul

11Alexandr11 [23.1K]

Answer:

$x1$

Step-by-step explanation:

We have:

$(x+5)(x-1)$

And we want to find the value of x such that the expression is positive. So, we can write this as the following inequality:

$(x+5)(x-1)>0$

Solve for the inequality. First, we can solve for the zeros like a normal quadratic. So, pretend the inequality is with an equal sign:

$(x+5)(x-1)=0$

Zero Product Property:

$x+5=0\text{ or } x-1=0$

On the left, subtract 5.

On the right, add 1.

So, our zeros are:

$x=-5, 1$

Since our inequality is a greater than, our answer is an "or" inequality with our answer being all the values to the left of our lesser zero and all the values to the right of our greater zero.

So, our solution is:

$x1$

And we're done!

7 0

3 years ago

Read 2 more answers

Simplify the expression below you must show all work to receive full credit

Marrrta [24]

Answer:

8w^2 I don't know why it is not on here, but I put it in an algebra calculator and everything. Good luck. :)

Step-by-step explanation:

Simply the radicals by multiplying and taking square roots.