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jok3333 [9.3K]
3 years ago
10

Simplify the expression below you must show all work to receive full credit

Mathematics
2 answers:
Marrrta [24]3 years ago
7 0

Answer:

8w^2 I don't know why it is not on here, but I put it in an algebra calculator and everything. Good luck. :)

Step-by-step explanation:

Simply the radicals by multiplying and taking square roots.

2\sqrt[4]{8w^3} * \sqrt[4]{32w^5}

= 2\sqrt[4]{8w^3} *2w\sqrt[4]{2w}

= 4w\sqrt[4]{16w^4}

=4w(2w)

=8w^{2}

KengaRu [80]3 years ago
7 0

Answer: Uhm... None of the options seem to be correct. The answer is: 8w^2

Step-by-step explanation:

2\sqrt[4]{8w^3}*\sqrt[4]{32w^5}

This is the same as;

2\sqrt[4]{(8w^3)(32w^5)}

2\sqrt[4]{256w^8}

2\sqrt[4]{4^4w^8}

2*4\sqrt[4]{w^8}\\ 8\sqrt[4]{w^8}\\8w^2

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What's is jiri's age ? <br> Pamela is 5 years younger than jiri. The sum of their ages is 37
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If Jiri is x, Pamela is x -5, and tehri ages combined would be 35 so;
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Step-by-step explanation:

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5. Solve using any method.<br> y = -x + 8<br> y=x+4
vlada-n [284]

Answer:

<h2>x = 2, y = 6 → (2, 6)</h2>

Step-by-step explanation:

\bold{ELIMINATION\ METHOD}\\\\\left\{\begin{array}{ccc}y=-x+8\\y=x+4&\TEXT{change the signs}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}y=-x+8\\-y=-x-4\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad0=-2x+4\qquad\text{add}\ 2x\ \text{to both sides}\\.\qquad2x=4\qquad\text{divide both sides by 2}\\.\qquad\boxed{x=2}\\\\\text{Put it to the second equation}\\y=2+4\\\boxed{y=6}

\bold{SUBSTITUTION\ METHOD}\\\\\left\{\begin{array}{ccc}y=-x+8&(1)\\y=x+4&(2)\end{array}\right\\\\\text{Substitute (1) to (2)}\\\\-x+8=x+4\qquad\text{subtract 8 from both sides}\\-x=x-4\qquad\text{subtract}\ x\ \text{from both sides}\\-x-x=-4\\-2x=-4\qquad\text{divide both sides by (-2)}\\\boxed{x=2}\\\\\text{Put it to the second equation}\\y=2+4\\\boxed{y=6}

7 0
3 years ago
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