What are the factors of the expression (y-2)(x+3)

2 answers:

7 0

(y - 2) and (x + 3).
<span>Since 2 and 3 are factors of 6, and you multiply 2 × 3 which equals 6 that is how you get your answer!</span>

ivanzaharov [21]4 years ago

5 0

(y-x) (2+3)= (yx)(5)
But am not sure it could be =(2-3) (y+x) = (1) (yx)

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Write the equation of the circle centered at (-4,6) with a diameter of 16

steposvetlana [31]

<span>Center:(-4,6)
The center of a circle is a point from which all points on a circle are the same distance.Radius:8
The radius of a circle is the length of a line segment from its center to its perimeter.
The radius is typically denoted as "r" or "R".Diameter:16
The diameter of a circle is any straight line segment that passes through the center of the circle and whose endpoints lie on the circle. It can also be defined as the longest chord of the circle.Circumference or (or Permieter) = 2*π*R = 2*3.14*8 = 50.2654824574367
The circumference of a circle is the distance around it.Area:201.061929829747
Area of a Circle is the amount of space occupied by the circle.The area of a circle is p times the radius squared, which is written: A = π*R2.</span>EquationStandard Form

The standard form for the equation oif a circle is
(x-a)2+(y-b)2=r2
And in our particular case:
(x--4)2+(y-6)2=82
(x+4)2+(y-6)2=82
(x+4)2+(y-6)2=64

General Form

The general form for the equation of a circle is
x2 + y2 + Ax + By + c = 0
We can get the general form by expanding the equation of the standard form
(x-a)2+(y-b)2=r2
(x--4)2+(y-6)2=82
(x+4)2+(y-6)2=64
x2+8x+16+y2-12y+36=64
x2+y2+8x-12y-12=0