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BaLLatris [955]
3 years ago
6

Find a positive number such that the sum of the number and its reciprocal is as small as possible?

Mathematics
1 answer:
WARRIOR [948]3 years ago
5 0
You're minimizing the function f(x)=x+\dfrac1x where x>0.

Take the derivative, set to zero and find the critical points:

f'(x)=1-\dfrac1{x^2}=0\implies1=\dfrac1{x^2}

This has two roots, x=\pm1, but we ignore the negative root.

Check the signs of the derivative to the left and right of x=1 and you'll see that f'(x) for x, and f'(x)>0 for x>1, which means a minimum occurs at x=1.
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-3<y<3 The filled in dot means 3 is greater than or equal to.

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Which of the following points would fall on the line produced by the point-slope form equation y - 8 = 4/5(x - 1) when graphed​
HACTEHA [7]
This says that x will equal -9

6 0
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Heyyy ummm... help??
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  • f(0) =  \frac{3}{2}
  • f(4) =   \frac{7}{2}

I tried them all and these two were correct, their solutions are as follows:

= f(x) = 1/2x + 3/2

= f(0) = 1/2 × 0 + 3/2

= f(0) = 0 + 3/2

= f(0) = 3/2

= f(x) = 1/2x + 3/2

= f(4) = 1/2 × 4 + 3/2

= f(4) = 2 + 3/2

= f(4) = 4+3/2

= f(4) = 7/2

So, that's how these two are correct.

7 0
2 years ago
Read 2 more answers
For a circle with a diameter of 6 meters, what is the measurement of a central angle (in degrees) subtended by an arc with a len
Sholpan [36]

Answer:

\boxed{\boxed{\theta=150^{\circ}}}

Step-by-step explanation:

We know that,

\text{Arc length}=r\cdot \theta

where,

r = radius,

θ = central angle in radian.

Given,

diameter = 6 m, so radius = 3 m.

\text{Arc length}=\dfrac{5}{2}\pi

Putting the values,

\Rightarrow \dfrac{5}{2}\pi=3\theta

\Rightarrow \theta=\dfrac{5}{2\times 3}\pi

\Rightarrow \theta=\dfrac{5}{6}\pi=\dfrac{5}{6}\times 180^{\circ}=150^{\circ}


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3 years ago
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