1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andre45 [30]
3 years ago
8

(7t^2)^3 simplified

Mathematics
2 answers:
Nikitich [7]3 years ago
7 0
343t^6

Words to take up 20 characters
mihalych1998 [28]3 years ago
3 0
(7t^2)^3

In this equation, you multiple the exponents to get 6.

2 x 3 = 6

So, the answer is: 7t^6
You might be interested in
State of the given functions are inverses
bonufazy [111]

Answer:

1) They are not inverses

2) They are inverses

Step-by-step explanation:

We need to find the composition function between these functions to verify if these functions are inverses. If f[g(x)] and g[f(x)] are equal to x they are inverses.

<u>1)</u>

<u>Let's find f[g(x)] and simplify.</u>

f[g(x)]=\frac{1}{2}g(x)+\frac{3}{2}

f[g(x)]=\frac{1}{2}(4-\frac{3}{2}x)+\frac{3}{2}    

f[g(x)]=\frac{7}{2}-\frac{3}{4}x

As f[g(x)] is not equal to x, these functions are not inverses.

2)

<u>Let's find f[g(x)] and simplify.</u>

f[g(n)]=\frac{-16+(4n+16)}{4}

f[g(n)]=\frac{-16+4n+16}{4}

f[g(n)]=\frac{4n}{4}

f[g(n)]=n

Now, we need to find the other composition function g[f(x)]

<u>Let's find g[f(x)] and simplify.</u>

g[f(x)]=4(\frac{-16+n}{4})+16

g[f(x)]=-16+n+16

g[f(x)]=n

Therefore, as f[g(n)] = g[f(n)] = n, both functions are inverses.

I hope it helps you!  

3 0
3 years ago
73 * 10 to the power of 2​
Verdich [7]
73(10)^2

730^2

answer: 532,900
7 0
2 years ago
What is the equation of the following line? Be sure to scroll down first to see
topjm [15]

Answer: (f)

Step-by-step explanation:

Given

Line that passes through (-\frac{1}{2},3) and (0,0)

Using two point form, equation of a line is given by

\Rightarrow \dfrac{y-y_1}{x-x_1}=\dfrac{y_2-y_1}{x_2-x_1}

Insert the values

\Rightarrow \dfrac{y-0}{x-0}=\dfrac{3-0}{-\frac{1}{2}-0}\\\\\Rightarrow \dfrac{y}{x}=-6\\\\\Rightarrow y=-6x

Thus, option (f) is correct

8 0
3 years ago
Can someone please help me
Ad libitum [116K]
Square root both sides. The unreduced answer is root 28. Now. To reduce root 28, you need to break it down into factors and hope one of them is a perfect square. 

4*7=28, and 4 is a square number. The square root of 4 is either positive or negative 2. Now that you've found that square, pull it out from under the square root symbol. Under the root symbol, you're left with 7 (not a perfect square).

Therefore, your answer is C
7 0
3 years ago
Read 2 more answers
You can show your work if u want to<br> Find 2 numbers if Their sum is −7 and their difference is 14
Pepsi [2]

The larger number is (-7+14)/2 = 3.5.

The smaller number is (-7-14)/2 = -10.5.

_____

The two equations a+b=-7, a-b=14 can be solved to get these results. It is genrally convenient to solve them by adding one to the other, or subtracting one from the other.

7 0
3 years ago
Other questions:
  • Is the z score corresponding to a number or score below the mean always negative?
    13·1 answer
  • It is possible to obtain a ""quick-and-dirty"" estimate of the mean of a normal distribution from the 50th percentile value on a
    14·1 answer
  • What is 28 equal to 14 plus 7w
    12·2 answers
  • Paul went to a movie and had 200$ to spend on himself and his friends.If a movie ticket costs 8$ and he wants to buy 40$ worth o
    11·1 answer
  • What is it please help me
    15·1 answer
  • Im Confused. Pls Help
    12·1 answer
  • The lengths of babies born at Tarth Hospital in the last year were normally distributed. The mean length was 50 cm and the stand
    9·1 answer
  • What is the area of the parallelogram?
    5·1 answer
  • The area of a rectangle is 27x2+27x-30 square feet. The length of the rectangle is 9x– 6 feet. What is the width of the rectangl
    14·1 answer
  • What is the total surface area of the square pyramid below?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!