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3 years ago

What about this one ?

Mathematics

2 answers:

Mazyrski [523]3 years ago

7 0

Download Photomath bro save my life

il63 [147K]3 years ago

6 0

For this case we have the following equation:
x ^ 2 + 18x + 32 = 0
Rewriting we have:
x ^ 2 + 18x = -32
By completing squares we have:
x ^ 2 + 18x + (18/2) ^ 2 = -32 + (18/2) ^ 2
Rewriting:
x ^ 2 + 18x + (9) ^ 2 = -32 + (9) ^ 2
x ^ 2 + 18x + 81 = -32 + 81
x ^ 2 + 18x + 81 = 49
(x + 9) ^ 2 = 49
Answer:
(x + 9) ^ 2 = 49
option 1

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In a certain Algebra 2 class of 29 students, 13 of them play basketball and 7 of them play baseball. There are 4 students who pl

Inessa [10]

Answer:

16/29

Step-by-step explanation:

P(A∪B) = P(A) + P(B) - P(A∩B)

P(basketball or baseball) = P(basketball) + P(baseball) - P(both)

= (13/29) + (7/29) - (4/29)

= 16/29

The probability that a randomly chosen student plays either sport is 16/29.

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3 years ago

Find the distance between the following pairs of points: C (1,6) .D (13.41).

worty [1.4K]

The person above is correct

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2 years ago

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

Alekssandra [29.7K]

In the given figure we can determine the coordinate of point M from the graph, we get:

$M=(\frac{d}{2},\frac{c}{2})$

We can also determine the coordinates of point N as:

$N=(\frac{a+b}{2},\frac{c}{2})$

Now, to determine the length of segment MN, we need to subtract the x-coordinate of M from the coordinates of N, we get:

$MN=\frac{a+b}{2}-\frac{d}{2}$

Subtracting the fractions we get:

$MN=\frac{a+b-d}{2}$

Now, to obtain the length of AB we need to subtract the x-coordinate of A from the x-coordinate of B.

The coordinates of A are determined from the graph:

$A=(0,0)$

The coordinates of B are:

$B=(a,0)$

Therefore, the length of segment AB is:

$AB=a$

Now we do the same procedure to determine the segment of CD. The coordinates of C are:

$C=(b,c)$

The coordinates of D are:

$D=(d,c)$

Therefore, CD is:

$CD=b-d$

Now, we determine MN as half the sum of the bases. The bases are AB and CD, therefore:

$MN=\frac{1}{2}(a+b-d)$

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1 year ago

Gonzalez Manufacturing borrowed $. Part of the money was borrowed at %, part at %, and part at %. The annual interest was $

Pavel [41]

Answer:

The answer is "rate 12%, 14%, 16% and value 4000, 10000, and 7000".

Step-by-step explanation:

Let the value is x, y, and z. so,

The value of x amount will be borrowed at 12% $= \frac{12}{100} \times x= 0.12x$

The value of y amount will be borrowed at 14% $= \frac{14}{100} \times x= 0.14x$

The value of z amount will be borrowed at 16% $= \frac{16}{100} \times x= 0.16x$

If the total amount= 21000

$\to x+y+z=21000$

If the total interest= 3000

calculating the total interest:

$\to 0.12x +0.14y +0.16z = 3000$

The overall amount borrowing at 12% and 14% was half as much as the amount borrowed at 16%.

$\to x + y = 2z\\\\\to x + y - 2z = 0$

by calculating the value we have 3 equations that are:

$\to x+y+z=21000\\\\\to 0.12.x +0.14.y +0.16z = 3000\\\\\to x + y - 2z= 0\\$

calculate the matrix by above-given value:

$\left[\begin{array}{ccc}1&1&1\\0.12&0.14&0.16\\1&1&-2\end{array}\right]$ $\left[\begin{array}{c}x&y&z\\ \end{array}\right] =\left[\begin{array}{c}21000&3000&0\\ \end{array}\right]$

by solving the above matrix we get:

$\left[\begin{array}{c}x&y&z\\ \end{array}\right] =\left[\begin{array}{c}4000&10000&7000\\ \end{array}\right]$

$\to \$ 4000 \text{ lent at} 12 \% \\\to \$ 10000 \text{ lent at} 14 \% \\\to \$ 7000 \text{ lent at} 16\%\\\\$

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3 years ago

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babunello [35]

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This display is more appropriate than, say, a line graph, because the graph is not supposed to show change over time, but just a snapshot of students' salaries after graduating.

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