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elena-s [515]
3 years ago
7

What about this one ?

Mathematics
2 answers:
Mazyrski [523]3 years ago
7 0
Download Photomath bro save my life
il63 [147K]3 years ago
6 0
For this case we have the following equation:
 x ^ 2 + 18x + 32 = 0
 Rewriting we have:
 x ^ 2 + 18x = -32
 By completing squares we have:
 x ^ 2 + 18x + (18/2) ^ 2 = -32 + (18/2) ^ 2
 Rewriting:
 x ^ 2 + 18x + (9) ^ 2 = -32 + (9) ^ 2
 x ^ 2 + 18x + 81 = -32 + 81
 x ^ 2 + 18x + 81 = 49
 (x + 9) ^ 2 = 49
 Answer:
 
(x + 9) ^ 2 = 49
 
option 1
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In a certain Algebra 2 class of 29 students, 13 of them play basketball and 7 of them play baseball. There are 4 students who pl
Inessa [10]

Answer:

16/29

Step-by-step explanation:

P(A∪B) = P(A) + P(B) - P(A∩B)

P(basketball or baseball) = P(basketball) + P(baseball) - P(both)

= (13/29) + (7/29) - (4/29)

= 16/29

The probability that a randomly chosen student plays either sport is 16/29.

3 0
3 years ago
Find the distance between the following pairs of points: C (1,6) .D (13.41).
worty [1.4K]
The person above is correct
8 0
2 years ago
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
Alekssandra [29.7K]

In the given figure we can determine the coordinate of point M from the graph, we get:

M=(\frac{d}{2},\frac{c}{2})

We can also determine the coordinates of point N as:

N=(\frac{a+b}{2},\frac{c}{2})

Now, to determine the length of segment MN, we need to subtract the x-coordinate of M from the coordinates of N, we get:

MN=\frac{a+b}{2}-\frac{d}{2}

Subtracting the fractions we get:

MN=\frac{a+b-d}{2}

Now, to obtain the length of AB we need to subtract the x-coordinate of A from the x-coordinate of B.

The coordinates of A are determined from the graph:

A=(0,0)

The coordinates of B are:

B=(a,0)

Therefore, the length of segment AB is:

AB=a

Now we do the same procedure to determine the segment of CD. The coordinates of C are:

C=(b,c)

The coordinates of D are:

D=(d,c)

Therefore, CD is:

CD=b-d

Now, we determine MN as half the sum of the bases. The bases are AB and CD, therefore:

MN=\frac{1}{2}(a+b-d)

Therefore, we have proven that the median of a trapezoid equals half the sum of its bases.

8 0
1 year ago
Gonzalez Manufacturing borrowed ​$. Part of the money was borrowed at ​%, part at ​%, and part at ​%. The annual interest was ​$
Pavel [41]

Answer:

The answer is "rate 12%, 14%, 16% and value 4000, 10000, and 7000".

Step-by-step explanation:

Let the value is x, y, and z. so,

The value of x amount will be borrowed at 12% = \frac{12}{100} \times x= 0.12x

The value of y amount will be borrowed at 14%= \frac{14}{100} \times x= 0.14x

The value of z amount will be borrowed at 16% = \frac{16}{100} \times x= 0.16x

If the total amount= 21000

\to x+y+z=21000

If the total interest= 3000

calculating the total interest:

\to 0.12x +0.14y +0.16z = 3000

The overall amount borrowing at 12% and 14% was half as much as the amount borrowed at 16%.

\to x + y = 2z\\\\\to x + y - 2z = 0

by calculating the value we have  3 equations that are:

\to x+y+z=21000\\\\\to 0.12.x +0.14.y +0.16z = 3000\\\\\to  x + y - 2z= 0\\

calculate the matrix by above-given value:

\left[\begin{array}{ccc}1&1&1\\0.12&0.14&0.16\\1&1&-2\end{array}\right]\left[\begin{array}{c}x&y&z\\ \end{array}\right] =\left[\begin{array}{c}21000&3000&0\\ \end{array}\right]

by solving the above matrix we get:

\left[\begin{array}{c}x&y&z\\ \end{array}\right] =\left[\begin{array}{c}4000&10000&7000\\ \end{array}\right]

\to \$ 4000 \text{ lent at} 12 \% \\\to \$ 10000 \text{ lent at} 14 \% \\\to  \$ 7000 \text{ lent at} 16\%\\\\

6 0
3 years ago
The university is trying to compile a visual display of the starting salaries of their most recent graduates which type of displ
babunello [35]
One type of display is a frequency distribution curve. 

This is a graph you are probably used to seeing, and often takes the form of a bar graph. 

The length of each bar indicates either the frequency or number of students within a certain salary range. It helps to get an idea of the most typical salaries students are earning in their first year.

This display is more appropriate than, say, a line graph, because the graph is not supposed to show change over time, but just a snapshot of students' salaries after graduating. 

4 0
3 years ago
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