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3 years ago

Which line segment has the same measure ST?

Mathematics

2 answers:

drek231 [11]3 years ago

7 0

SR smart one whats the opposite of that line?

kow [346]3 years ago

6 0

Answer:

SR is the line segment has the same measure ST .

Step-by-step explanation:

In the Δ SXR and ΔSXT .

(1) RX = XT

(As given in the figure )

(2) ∠SXR = ∠ SXT = 90°

(As given in the figure)

(3) SX = SX

(Common sides of both triangle )

Thus by using SAS congurence property .

Δ SXR ≅ ΔSXT

Thus

ST = SR

(By using the corresponding sides of the congurent triangle .)

Therefore SR is the line segment has the same measure ST .

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To eliminate the x terms and solve for y in the fewest steps, by which constants should the equations be multiplied by before ad

aliya0001 [1]

Answer:

See below.

Step-by-step explanation:

Here is an example:-

Solve by elimination:

2x - 3y = 0

3x + 2y = 13

To eliminate the y terms Multiply the first equation by 2 and the second by 3. This gives:

4x - 6y = 0

9x + 6y = 39 Adding the 2 equations:

13x + 0 = 39

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x = 39/13 = 3

Finally we find y by plugging x = 3 into the first equation:

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2 years ago

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Answer:

Step-by-step explanation:

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3 years ago

Simplify $\frac{1+\sqrt{2}}{2+\sqrt{3}}$. Your solution can be converted to the form $A(1+\sqrt{B})-(\sqrt{C}+\sqrt{D})$, where

Zina [86]

Answer:

A+B+C+D = 13

Step-by-step explanation:

The given expression is:

$\dfrac{1+\sqrt{2}}{2+\sqrt{3}}$

We have to simply it and express it in the form of:

$A(1+\sqrt{B})-(\sqrt{C}+\sqrt{D})$

Multiply and divide the given expression with $2-\sqrt 3$ :

$\dfrac{1+\sqrt{2}}{2+\sqrt{3}} \times \dfrac{2-\sqrt 3}{2-\sqrt 3}\\\Rightarrow \dfrac{(1+\sqrt{2}) \times (2-\sqrt 3)}{(2+\sqrt{3})\times (2-\sqrt 3)}\\\Rightarrow \dfrac{2+2\sqrt2-\sqrt3-\sqrt6}{2^2-(\sqrt{3})^2}\\\Rightarrow \dfrac{2+2\sqrt2-\sqrt3-\sqrt6}{4-3}\\\Rightarrow \dfrac{2(1+\sqrt2)-(\sqrt3+\sqrt6)}{1}\\\Rightarrow 2(1+\sqrt2)-(\sqrt3+\sqrt6)$

It is the simplified form of given expression.

Formula used:

$(a+b)(a-b) = a^{2} -b^{2}$

Comparing the simplified expression with $A(1+\sqrt{B})-(\sqrt{C}+\sqrt{D})$

$2(1+\sqrt2)-(\sqrt3+\sqrt6)=A(1+\sqrt{B})-(\sqrt{C}+\sqrt{D})\\\Rightarrow A =2, B=2, C=3\ and\ D=6$

So, value of

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4 years ago

Can you tell me how to calculate R for below Matrix ?

scoray [572]

Answer:

The rank of the matrix is 3.

Step-by-step explanation:

Consider the prided information.

$x=\begin{bmatrix}x_1\\ x_2\\ x_3\end{bmatrix}=\begin{bmatrix}9&2&6&5&8\\ 12&8&6&4&10\\ 3&4&0&2&1\end{bmatrix}$

Reduce the matrix in row echelon form as shown:

$R_1\:\leftrightarrow \:R_2\begin{bmatrix}12&8&6&4&10\\ 9&2&6&5&8\\ 3&4&0&2&1\end{bmatrix}\\$

$R_2\:\leftarrow \:R_2-\frac{3}{4}\cdot \:R_1\ and\ R_3\:\leftarrow \:R_3-\frac{1}{4}\cdot \:R_1\\\\\begin{bmatrix}12&8&6&4&10\\ 0&-4&\frac{3}{2}&2&\frac{1}{2}\\ 0&2&-\frac{3}{2}&1&-\frac{3}{2}\end{bmatrix}$

$R_3\:\leftarrow \:R_3+\frac{1}{2}\cdot \:R_2\\\begin{bmatrix}12&8&6&4&10\\ 0&-4&\frac{3}{2}&2&\frac{1}{2}\\ 0&0&-\frac{3}{4}&2&-\frac{5}{4}\end{bmatrix}$

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Answer:

Step-by-step explanation:

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