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Marat540 [252]
3 years ago
11

How many cubes that have an edge length 1/2 inch are needed to fill a rectangular prism with a volume of 6 cubic inches (2 inche

s wide x 3 inches long by 1 inch tall)?
Mathematics
2 answers:
serious [3.7K]3 years ago
8 0
If I’m not right I think u will need 24
ExtremeBDS [4]3 years ago
6 0

Answer:

You will need 24

Step-by-step explanation:

1/2 inch * 2 is 1 inch so for how wide it is you have two therefore you will need 4 on that area next we need to fin how long it is we are going to need 6 1/2 inches to make three so multiply 6 and 4 boom you get 24

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A truck can be rented from Company A for $100 a day plus $0.60 per mile. Company B charges $60 a
tangare [24]

Answer:

100 + 0.6m = 60 + 0.7m

Step-by-step explanation:

Company A: 100 + .6m

Company B: 60 + .7m

Same; =

100 + 0.6m = 60 + 0.7m

8 0
3 years ago
Multiplying a trinomial by a trinomial follows the same steps as multiplying a binomial by a trinomial. Determine the degree and
charle [14.2K]
To determine the degree of the product of the given trinomials, you would multiply the term with the highest degree of each trinomial together. Both trinomials are degree 2, and when you multiply x2<span> by </span>x2<span>, you add the exponents to get </span>x4<span>. Thus, the degree of the product is 4. If the product is degree 4, and there is only one variable, the maximum number of terms is 5. There can be an </span>x4<span> term, an </span>x3<span> term, an </span> x2<span> term, an </span>x<span> term, and a constant term. </span>
6 0
4 years ago
At east school each of the 45 classrooms have an average of 22 students at West School each of the 42 classrooms have an average
Deffense [45]
East= 45 x 22 = 990 students
west= 42 x 23 = 996 students
996 - 990 = 6 students
990 - 996 = -6 students

There are 6 more students at West school than East school. There are -6 more students at East school than West school.

Hope it helps!


4 0
3 years ago
The two-way relative frequency table shows the relative frequencies of late-night workers and day workers who do or do not drink
ArbitrLikvidat [17]
The answer is 0.267% I hope that I helped thank you!!!!!
3 0
3 years ago
Read 2 more answers
At the start of the year, 15 chameleons were introduced into a zoo. The population of chameleons is expected to grow at a rate o
bearhunter [10]

Answer:

option-B

Step-by-step explanation:

We are given

At the start of the year, 15 chameleons were introduced into a zoo

so, P_0=15

The population of chameleons is expected to grow at a rate of 41.42% every year

so, r=0.4142

and x represents the number of years since the chameleons were introduced into the zoo

now, we can set equation to find total population

and we get

P(x)=P_0(1+r)^x

now, we can plug values

P(x)=15(1+0.4142)^x

P(x)=15(1.4142)^x

Average rate of change between 2 years and 4 years:

we can use formula

A_1=\frac{P(4)-P(2)}{4-2}

now, we can plug values

A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}

A_1=14.99914

Average rate of change between 4 years and 6 years:

we can use formula

A_2=\frac{P(6)-P(4)}{6-4}

now, we can plug values

A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}

A_2=29.99770

Average rate of change between 6 years and 8 years:

we can use formula

A_3=\frac{P(8)-P(6)}{8-6}

now, we can plug values

A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}

A_3=59.99425

now, we will check each options

option-A:

we can see that

A_3-A_2=30

A_3-A_2=30

So, this is FALSE

option-B:

A_1=\frac{1}{2}A_2

So, this is TRUE

option-C:

This is FALSE

option-D:

we got

A_1=\frac{1}{2}A_2

so, this is FALSE


5 0
3 years ago
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