If I buy 3 4/5kg of cherries and 2 1/4 of strawberry's what is the Mass kilograms of fruit
1 answer:
If you would like to know how many kilograms of fruit do you have, you can calculate this using the following steps:
3 4/5 kg of cherries + 2 1/4 kg of strawberries = 3 4/5 + 2 1/4 = 19/5 + 9/4 = 76/20 + 45/20 = (76 + 45) / 20 = 121/20 = 6 1/20 kg of fruit
The correct result would be 6 1/20 kilograms of fruit.
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Answer:
6:3:8
Step-by-step explanation:
We need to find the amount of:
Frogs= Joes has 6
Snakes= Joe has 3
Hamster= Joe has 8
So, the ratio of Joe's frogs and snakes to hamsters is 6: 8 : 3.
Hope that helped! :)
Answer:
15
Step-by-step explanation:
We can use the fact that, for 
,
Notice that
![\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1{1-x}\right]=\dfrac1{(1-x)^2}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cleft%5B%5Cdfrac1%7B1-x%7D%5Cright%5D%3D%5Cdfrac1%7B%281-x%29%5E2%7D)
so that
![f(x)=\displaystyle\frac5{(1-x)^2}=5\frac{\mathrm d}{\mathrm dx}\left[\sum_{n=0}^\infty x^n\right]](https://tex.z-dn.net/?f=f%28x%29%3D%5Cdisplaystyle%5Cfrac5%7B%281-x%29%5E2%7D%3D5%5Cfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cleft%5B%5Csum_%7Bn%3D0%7D%5E%5Cinfty%20x%5En%5Cright%5D)
By the ratio test, this series converges if
so the series has radius of convergence 
.
A² + b² = c²
20² + n² = (n+2)²
400+ n² = (n+2)(n+2)
400 + n²=n² + 2n + 2n +4
400 + n² = n² +4n +4
400 + n²-n² = n²-n² + 4n+4
400 = 4n + 4
400-4 = 4n +4-4
396 = 4n
396/4 = 4n/4
n= 99
20²+ 99² = (99+2)²
400 + 9801 =10201
10201=10201
