Let h=height of water
Let r=radius of water surface
r/h=16/8 =2, so r=2h.
The volume of water is:
v=(1/3)×π×r²×h
=(1/3)×π×(2h)²×h
=4/3πh³
dv/dh=4πh^2
By chain rule:
dv/dt=dv/dh×dh/dt
but
dv/dt=4
thus:
4=(4πh)×dh/dt
dh/dt=4/(4πh²)
when h=6cm we have:
dh/dt=4/(4π6²)
=0.00884 cm³/min
3,1
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Answer:
The x-intercept is (-6,0)
8.2 Is the answer I believe!
Answer:
The potential energy of the ball having 2kg mass would be
J
Step-by-step explanation:
I am assuming the ball has a mass of 2 kg, as you have not mentioned the mass of a ball.
Considering the formula for calculating the gravitational potential energy

As
kg
Acceleration of gravity = g = 9.8 
As the ball is on the height = h = 20 meters
So,

J
Therefore, the potential energy of the ball =
J
Keywords: potential energy, Gravitation potential energy
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