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2 years ago

Graph the function need ASAP help Is it a, b , c or d?

Mathematics

2 answers:

natima [27]2 years ago

8 0

Answer:

y = 2x - 2

Step-by-step explanation:

Start with

y = mx + b

The graph shows the y-intercept -2.

We have y = mx - 2

slope = m = rise/run

The slope is rise of 2 and run of 1, so m = 2.

y = 2x - 2

sveta [45]2 years ago

7 0

Answer:

Step-by-step explanation:

(the line is a / shape, so the slope is positive)

(the line crosses the y axis at (0,-2)

(using the above information, the equation is y=2x-2)

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Find the magnitude of AB. A(-2, 6), B(1, 10) O A 2 OB. ✔️15 O C.5 OD ✔️2

natita [175]

Answer:

C. 5

Step-by-step explanation:

Use the Distance Formula.

Substitute the values of x1 , y1 , x2 , and y2 .

|AB|² =|(1--2)²+(10-6)²|

|AB|² = |9+16|

|AB| = √ 25

|AB| =5

6 0

3 years ago

What is polynomial?

shtirl [24]

Answer:

an expression of more than two algebraic terms, especially the sum of several terms that contain different powers of the same variable(s).

5 0

3 years ago

5cosx -2sin(x/2) +7=0 Help me to find x step by step pls

miskamm [114]

Answer:

x = 180

Step-by-step explanation:

First, you need to know

1. Double-angle formula:

cos(2x) = $cos^{2}x - sin^{2}x$

2. Pythagorean identity:

$cos^{2}x + sin^{2}x = 1$

Back to your problem, replacing the variable by the above:

$5cosx-sin\frac{x}{2}+7 = 0$

$5(cos^{2}\frac{x}{2}-sin^{2}\frac{x}{2}) - 2sin\frac{x}{2} + 7 = 0$ By Double-angle formula

$5(1 - 2sin^{2}\frac{x}{2}) - 2sin\frac{x}{2} + 7 = 0$ By Pythagorean identity

Given $y = \frac{x}{2}$

$5(1-2sin^{2}y) - 2siny + 7 = 0$

$10sin^{2}y+2siny-12=0$

$5sin^{2}y+siny-6=0$

$(5siny + 6)(siny - 1)=0$ , we know -1 < sinx < 1, for every x ∈ R

$siny = 1, y =90$

$y = \frac{x}{2}$

$x = 180$

8 0

3 years ago

Rewrite with only sin x and cos x.

amm1812

Answer:

sin2x-cosx
2sinx.cosx -cosx
cosx (2sinx-1)

5 0

2 years ago

Can anybody help with this

iris [78.8K]

100 =d

your welcome lol

8 0

3 years ago