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Aleks04 [339]
3 years ago
7

If f(x)= 15x+7x and g(x)= x^2-5x, find (f+g)(x)

Mathematics
1 answer:
cupoosta [38]3 years ago
7 0

Answer:

(f+g)(x) = x^2 +10x +7

Step-by-step explanation:

(f+g)(x) = f(x) +g(x) = (15x +7) +(x^2 -5x)

= x^2 +x(15 -5) +7

= x^2 +10x +7

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What is the area of a rectangle with a length of 9 and a width of 17?
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Answer:

153 units squared

Step-by-step explanation:

To solve, multiply your length by your width.

A=lw\\A=9(17)\\A=153

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3 years ago
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A handyman charges a fixed rate of R to visit a customers house. In addition, the hardy man charges an hourly rate for H for eac
aksik [14]

Answer:

T == R + NH

Step-by-step explanation:

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The sum is then ...

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4 0
3 years ago
Plz help!!
inysia [295]
<span>1. 5564÷91
I know that 9 * 6 = 56
5564 rounds to 5600
91 rounds to 9
Since 56/9 = 6, then 5600/90 is the same as 560/9 = 60
The estimate is 60

2. </span><span>5391÷25
5391 sounds to 5400
25 is 1/4 of 100.
That means when you divide by 25, you can divide by 100 and multiply by 4.
5400/100 = 54
54 * 4 = 216
Estimate: 216

3. </span><span>explain how to estimate 498÷12
48/12 = 4
498 is little more than 480, so 498/12 is little more than 40

4. </span><span>which is the closest estimate for 2130÷ 33
A.7 B.17 C.70 D.700

2130/33
Round off the numerator and denominator to
2100/30
Reduce the fraction
210/3
Since I know that 21/3 = 7, then 210/3 = 70
Estimate: 70
</span>
8 0
3 years ago
Suppose that you believe that contractor 1 is twice as likely to win as contractor 3 and that contractor 2 is three times as lik
Ray Of Light [21]

Answer:

probability that contractor 1,2 and 3 win is 33%,50% and 17% respectively

Step-by-step explanation:

assuming that there are no other contractors then:

probability that 1 , 2 or 3 win = 1

denoting as X= probability that contractor 3 wins , then assuming that only one wins , we have

probability that 1 , 2 or 3 win = 1

probability that contractor 1 wins + probability that contractor 2 wins + probability that contractor 3 wins = 1

2*P(X) + 3*P(X) + P(X) = 1

6*P(X) = 1

P(X) =1/6

then

-probability that contractor 1 wins = 2/6 (33%)

-probability that contractor 3 wins = 3/6 (50%)

-probability that contractor 3 wins = 1/6 (17%)

3 0
2 years ago
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