Answer:
the answer is triangles ABC and DEC are similar
Step-by-step explanation:
angle C is a common angle for both triangles
angle D is equal to angle A ( corresponding angles)since they are parallel
angle B is also equal to angle B for the same reason as angle D and A
since the three angles of the two angles are equal they are similar
Answer:
ok so we have to make it so we can get rid of one of the varibles by adding or subtracting
so lets multiply the first one by 4
120x+16y=4160
minus the second one so
108x=2160
divide by 108
x=20
then we just plug in
12(20)+16y=2000
240+16y=2000
-240
16y=1760
divide by 16
y=110
(20,110)
Hope This Helps!!!
Answer:
Option B is correct.
Step-by-step explanation:
We have given a triangle ABC and EDC please look at the figure
We can see that AE and BD are transversal therefore, ∠EAB=∠AED being alternate interior angles
And ∠ACB=∠DCE are vertically opposite angles hence, equal
So, by AA similarity postulate the above to triangles are similar
ΔABC
ΔEDC
Therefore, Option B is correct that is Triangle ABC is similar to triangle EDC , because m∠3 = m∠4 and m∠1 = m∠5
NOTE: m∠3 = m∠4 corresponds to m∠ACB=m∠DCE
And m∠1 = m∠5 corresponds to m∠EAB=m∠AED