Answer:
0.00382
Step-by-step explanation:
because of the -3, you will move the decimal place to the left three units
You didn’t word this right... but I’m guessing the answer would be 12
So we are trying to find this red line's length.
We can either find it directly, or use the blue line firs, and then use it as a leg for the green triangle.
So the blue leg is a hypotenuse for two of the edges. So:
![blue^2 = leg^2 + leg^2](https://tex.z-dn.net/?f=blue%5E2%20%3D%20leg%5E2%20%2B%20leg%5E2)
from the Pythagorean Theorem
OR
![blue = \sqrt{leg^2 + leg^2}](https://tex.z-dn.net/?f=blue%20%3D%20%20%5Csqrt%7Bleg%5E2%20%2B%20leg%5E2%7D%20)
Which works out to:
![blue = \sqrt{10^2 + 10^2} = \sqrt{100+100} = \sqrt{200} = \sqrt{(100)(2)}=10 \sqrt{2}](https://tex.z-dn.net/?f=blue%20%3D%20%20%5Csqrt%7B10%5E2%20%2B%2010%5E2%7D%20%3D%20%20%5Csqrt%7B100%2B100%7D%20%3D%20%5Csqrt%7B200%7D%20%3D%20%20%5Csqrt%7B%28100%29%282%29%7D%3D10%20%5Csqrt%7B2%7D%20%20%20%20)
So now that we have that, using the Pythagorean Theorem again gives:
![red = \sqrt{blue^2 + 10^2} = \sqrt{(10 \sqrt{2})^2+10^2}= \sqrt{200+100}= \sqrt{300}](https://tex.z-dn.net/?f=red%20%3D%20%20%5Csqrt%7Bblue%5E2%20%2B%2010%5E2%7D%20%3D%20%20%5Csqrt%7B%2810%20%5Csqrt%7B2%7D%29%5E2%2B10%5E2%7D%3D%20%5Csqrt%7B200%2B100%7D%3D%20%5Csqrt%7B300%7D)
![\sqrt{300}= \sqrt{100*3}=10 \sqrt{3}](https://tex.z-dn.net/?f=%20%5Csqrt%7B300%7D%3D%20%5Csqrt%7B100%2A3%7D%3D10%20%5Csqrt%7B3%7D%20%20%20)
So the length of the red line is found that way.
But wait! There's more!
As it turns out, the red line can be found with an easier way that works with cubes and boxes (cuboids). It's really easy:
![a^2 + b^2+c^2=d^2](https://tex.z-dn.net/?f=a%5E2%20%2B%20b%5E2%2Bc%5E2%3Dd%5E2)
Where a, b, and c are all 10m, and d is the red line. This greatly reduces the math:
![d = \sqrt{10^2+10^2+10^2} = \sqrt{100+100+100} = \sqrt{300}](https://tex.z-dn.net/?f=d%20%3D%20%20%5Csqrt%7B10%5E2%2B10%5E2%2B10%5E2%7D%20%3D%20%5Csqrt%7B100%2B100%2B100%7D%20%3D%20%20%5Csqrt%7B300%7D%20)
which gives the same answer as above, which you can see.
<h3>
Answer: C) 4</h3>
=====================================================
Work Shown:
Applying the tangent-secant theorem will allow us to solve for x
x*(x+5) = (x+2)^2
x^2+5x = (x+2)*(x+2)
x^2+5x = x^2+4x+4
5x = 4x + 4 ..... subtracting x^2 from both sides; terms cancel
5x-4x = 4
x = 4
------------------
Check:
Plug in x = 4
x*(x+5) = (x+2)^2
4*(4+5) = (4+2)^2
4*(9) = (6)^2
36 = 36
The answer is confirmed.