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nevsk [136]
3 years ago
6

A number h is not less than 7

Mathematics
2 answers:
Valentin [98]3 years ago
8 0
H>7 is your answer :)
Sonja [21]3 years ago
8 0
H >= 7

h is NOT less than 7
so any number that is greater than or equal to seven are potential values for h...
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What is the qoutient of 1/6 and 2/9
beks73 [17]

Answer:

\frac{3}{4}

Step-by-step explanation:

To find the quotient, we first need to know what quotient means.

Quotient is the solution to division problems.

So here is how we have to do this, first we identify our fractions:

\frac{1}{6}   and    \frac{2}{9}

Next, we must turn the fraction we are dividing by into a reciprocate:

\frac{2}{9} turns into \frac{9}{2}

Now we have \frac{1}{6} and \frac{9}{2}

Next, we multiply!:

\frac{1}{6} x \frac{9}{2} = \frac{9}{12}

Simplified:

\frac{3}{4}

8 0
3 years ago
Read 2 more answers
What should you do first to simplify the expression (43 + 9) ÷ 76 + 5?
Vaselesa [24]
Do the parentheses first
5 0
3 years ago
Easiest question in the world no joke this time
Volgvan

Question #25:

One way to solve this is by multiplying the number of packages per serving by the number of guests.

1/4 * 16 = 4 packages to serve 16 guests. This means he doesn't have enough.

A second way to solve this is by diving the number of packages by the number of packages it takes to make on serving.

3 1/2 ÷ 1/4 = 14 guests he can serve. This means he doesn't have enough.

Question #26:

First, find common denominators.

2/3 = 8/12

1/4 = 3/12

Second, subtract.

8/12 - 3/12 = 5/12

Therefore, the tank is 5/12 full at the end of the trip.

Question #27:

1/2 is cut off then 1/3 is cut off. This means 3/6 was cut off to bundle newspapers, then 1/6 was cut off to make parcel. In all, 4/6 was cut off the original string. Afterwards, 2/6 was left over. So, just multiply; 2 * 3 = 6.

Therefore, the original string was as a total of 6 meters.

Best of Luck!

3 0
3 years ago
HELP! im sooooooooooo confused
Mama L [17]

Answer:

wow this is hard let me do the math hold on

Step-by-step explanation:

6 0
2 years ago
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Determine whether the relation is a function. find the domain and range
11Alexandr11 [23.1K]
What’s the question
5 0
3 years ago
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