1.40 under budget I think, hope this is some help
Answer:
2y-3x+15 = 0
Step-by-step explanation:
let the equation of the perpendicular line: y=mx+c.
Given equation : 2x+3y=12
=> y=-2/3 x+4
so the sope of the equation is m1= -2/3.
as the two lines are mutually perpendicular,
so, m1*m2=-1
=> (-2/3)*m2= -1
=> m2= 3/2
the paerpendicular line : y=(3/2) x+c.
this line pass through (7,3)
so, 3 = (3/2)*7+c
=> c = -15/2
so the perpendicular line y = (3/2)*x -15/2
=> 2y-3x+15 = 0
Answer:wanna hang
Step-by-step explanation:
Answer:
D. x-intercept is -5 and the y-intercept is -2
