Answer: classification key ! :))
Explanation:
Answer:
The correct answer is - Mouse - chicken - sheep - baboon - human
Explanation:
According the graph there are different group of organisms presents and the individual graph lines represnt the time they take to reach various or different carnegie stages.
To complete the 20th carnegie stage chicken takes 8 days aproximately, mouse takes 13 days and sheep takes 30 days according the graph representation.
Baboon takes almost 41 days to complete the 20th carnegie stage whereas human takes maximum time which is 55 days so , the corrcet order from fastest to the slowest would be as follows:
Mouse - chicken - sheep - baboon - human
Answer:
a) water will move from the cell into the beaker acroas the cell membrane
b) solutes will diffuse into the cell
Explanation:
a) Osmosis is the phenomenon that describes the movement of water from a region of low solute concentration (high water concentration) to a region of high solute concentration (low water concentration) across a semi-permeable membrane. In this case, since the inside of the cell contains a lesser concentration of solute (150mm), water containing dissolved solutes will move osmotically into the solution of the beaker, which has a higher concentration of solute (500mM) via the cell membrane (semi-permeable membrane).
b) Diffusion involves the movement of particles or molecules from a region where they are highly concentrated to a region where they are less concentrated. In this case, solutes/ions will diffuse from the beaker (outside the cell) containing 500mM of solute INTO THE CELL containing 150mM of solute.
Answer:
When monchondria stops you would be able to control your ATP.
Explanation:
Answer:
a. the environmental variance (VE) = 3.5 g ²
b. 17.5 g ² for population
c. the heritability of broad sense (H2) = 0.83
Explanation:
a.With the information we have we can infer that environmental factors influence A, which is considered isogenic, thus, the environmental variance (VE) = 3.5 g ²
b.When studying population B, comparing it without environmental changes with respect to population A, we found that its total variance (VT) = 21.0g ²
We generate the following formula with the data obtained previously to find the genetic variation
VT = VE + VG
then VG = VT-VE
replacing data:
VG = 21.0 - 3.5 = 17.5 g ² for population
c. Regarding the heritability of broad sense (H2) in population B, we can reach the result with the data previously obtained like this:
H2 = VG / VT = 17.5 / 21.0 = 0.83