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vesna_86 [32]
3 years ago
9

What is the factored form x^3 - 1 ?

Mathematics
1 answer:
amid [387]3 years ago
7 0

Answer: x^3 - 1 = (x - 1)(x^2 + x + 1)

Explanation:

This is a type of factorizing called the sum or difference of 2 cubes:

a^3 - b^3 = (a - b)(a^2 + ab + b^2)

The sum of the cubes is factored as:

a^3 + b^3 = (a + b)(a^2 - ab + b^2)

In this case, we have: x^3 - 1 so follow the rule above.

x^3 - 1 = (x - 1)(x^2 + x + 1)

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If secθ = 13\5 and 270° < θ < 360°, then tanθ = _____. -12\5 -5\12 5\12 12\5
r-ruslan [8.4K]

Answer:

tanΘ = - \frac{12}{5}

Step-by-step explanation:

Using the trigonometric identity

tan²Θ + 1 = sec²Θ, thus

tan²Θ + 1 = (\frac{13}{5} )² = \frac{169}{25} ( subtract 1 from both sides )

tan²Θ = \frac{144}{25} ( take the square root of both sides )

tanΘ = ± \sqrt{\frac{144}{25} }

Since 270 < Θ < 360 , that is the fourth quadrant where tan Θ < 0, thus

tanΘ = - \frac{12}{5}

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