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Elden [556K]
4 years ago
15

A public interest group hires students to solicit donations by telephone. After a brief training period students make calls to p

otential donors and are paid on a commission basis. Experience indicates that early​ on, these students tend to have only modest success and that 80​% of them give up their jobs in their first two weeks of employment. The group hires 7 ​students, which can be viewed as a random sample.
Mathematics
1 answer:
IceJOKER [234]4 years ago
8 0
I need help with the answer?
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I need help!! Can someone help me?¿
wolverine [178]
Sorry don't know explane the question
7 0
4 years ago
If _______ , what is f^-1(x)?<br> f–1(x) = 9x + 18<br> ________<br> f–1(x) = 9x + 2<br> ________
Dennis_Churaev [7]
If f(x)=1/9x-2
then f^-1(x) will be
lets assume f(x)=y
y=1/9x-2
y+2=1/9x
9(y+2)=x
f^-1(x)=9(y+2)

rest u can do with the same method

5 0
4 years ago
Read 2 more answers
The following are the ages (years) of 5 people in a room:
slava [35]

Answer:

The age of the person who entered the room is 15

Step-by-step explanation:

We are given:

Ages of 5 people in a room are:

17, 16, 15, 17, 22

A person enters room, and then the mean age of 6 people is 17.

We need to find the age of person who entered the room.

The formula to calculate mean is: Mean=\frac{Sum\:of\:all\:data\:values}{Number\:of\:data\:Values}

Now, in question we are given mean of 6 people that is 17

The age of 5 people are given while age of one person who enters the room is unknown.

Let age of person whose age is unknown= x

Now finding x using mean formula

Mean=\frac{Sum\:of\:all\:data\:values}{Number\:of\:data\:Values}\\17=\frac{17+16+ 15+ 17+ 22+x}{6}\\17=\frac{87+x}{6}\\17*6=87+x\\102=87+x\\x=102-87\\x=15

So, The value of x: x=15

Hence, the age of the person who entered the room is 15

4 0
3 years ago
HELPPP!!!! Both questions are incredibly confusing to me !!!!!
Darya [45]

Answer:

Step-by-step explanation:

I'm going to start with problem 3. You need to become familar with the kind of tricks teachers play on you.

Problem 3 depends on getting RS = RW.

RT = RT                                    Reflexive property

<STR = <WTR                           A straight line having 1 rt angle  actually has 2

ST = TU                                    They are marked as equal

Triangle STR=Triangle WTR    SAS

RS = RW                                    Corresponding parts of = triangles are =

8x = 6x + 5                                Subtract 6x from both sides

8x -6x = 6x - 6x + 5                   Combine

2x = 5                                         Divide by 2

2x/2 = 5/2

x = 2.5

RU = 6*2.5 + 5

RU = 15 + 5

RU = 20

Now we can play with Question 4.

This question depends on the method used in three, although not entirely.

What you need to know is that W is on RT when you take a ruler and make RT longer. You can put W anywhere as long as it is on RT when it is made longer.

Directions

Make RT longer. Draw down and to your right.

Put a point anywhere on the length starting at T. Label this new point as W. There's your W. It goes anywhere on the part of RT made longer.

Draw UW.

Label UW as 8

Now draw another line from S to W. Guess what? By the methods used in question 3, it's also 8. So SW = 8

TW = TW                        Reflexive

<UTW = STW                 Same reason as in 3. UtW is a right angle

UT = ST                          Given (the marking tells you so.

ΔUTW = ΔSTW              SAS

UW = SW                       Corresponding parts of = triangles are =

SW  = 8

7 0
3 years ago
What is 4+3x6x(4+3³)² please show work tysm
LUCKY_DIMON [66]
Answer: 17302

Explanation: This problem requires PEMDAS.

Step 1: Parentheses

(4+3^3) = (4+27) = 31

Step 2: Exponents

31^2 = 961

Step 3: Multiplication

3x6= 18
18x961=17298

Step 4: Addition

17298 + 4 = 17302
8 0
3 years ago
Read 2 more answers
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