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Leya [2.2K]
3 years ago
7

Help! Due in 5 minutes

Mathematics
1 answer:
Flauer [41]3 years ago
6 0
The first one is 2/3
Second one is 1/3 2/3 and 3/3
Last one is may be because they are equal?
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if an experiment consist of throwing a die and then drawing a letter at random from the English alphabet, how many points are th
Rama09 [41]
So throwing a die hs 6 choices
26 letters
not sure what the points are
if you want to list all of the options then
multipliy 6 by 26
6 times 26=156
so 156 spaces
4 0
3 years ago
Hello please help thanks i’ll give brainliest!
erastovalidia [21]

Answer: A

Step-by-step explanation: Hope this help :D

8 0
3 years ago
Please help me with this
Masja [62]

Answer:

c = a - 16

Step-by-step explanation:

Given

a = b + 12 ( subtract 12 from both sides )

a - 12 = b

Substitute b = a - 12 into b = c + 4

a - 12 = c + 4 ( add 12 to both sides )

a = c + 16  ( subtract 16 from both sides )

c = a - 16

5 0
2 years ago
Nathan has just bought a new car. He models the value, V, in dollars, of the car after t years as V(t) = 21,000(0.861)t. Based o
UkoKoshka [18]

Answer:

13.9%

Step-by-step explanation:

The value of car is modeled as:

V(t)=21,000(0.861)t

Here we can see that, each year Nathan has considered 0.861 of the previous year value or we can say that Nathan has considered 86.1% of the previous year value. So,

100-86.1=13.9

We subtract the percentage value considered from 100 to find out the percentage decrease in the value of the car.

The value of new car is decreasing by 13.9% each year.  

4 0
3 years ago
Please Help!!<br> f(x) = square root of x plus 7 ; g(x) = 8x -11 <br> Find f(g(x))
Sonja [21]

I'm not sure if you mean ( \sqrt{x + 7} ) or ( \sqrt{x}  + 7 ) I solved it both ways .

f(x) =  \sqrt{x + 7}  \\  \\ f( \: g(x) \: ) =  \sqrt{(8x - 11)+ 7}  \\  =  \sqrt{8x - 11 + 7}  \\   =  \sqrt{8x - 4}  \\  = 2 \sqrt{2x - 1}

____o_____o______

f(x) =  \sqrt{x}  + 7 \\  \\ f( \: g(x) \: ) =  \sqrt{(8x - 11)}  + 7 \\  =  \sqrt{8x - 11}   + 7\\

I hope I helped you^_^

8 0
3 years ago
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