(c+3)-2c-(1-3c)=2
c+3-2c-1+3c=2
2c+2=2
2c=0
c=0
<span>you're given both arcs, minor and major, or near and far arcs, all you need to do, is really plug them in</span>
X by its self is always 1x
1x+8=-15 you have to get rid of 8 by subtracting on both sides
1x=-23 now get rid of 1 by dividing on both sides
x=-23
You can set them equal to each other so -3x+4=4x-10 and then you add 3x and 10 on both sides and get7x=14 and then divided both sides by 7 and get x = 2 and check by plugging in and you get -2 for y on both so solution is x=2
