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rewona [7]
3 years ago
14

There are 6 marbles in a bag. 4 were red and 2 were blue what is the probability that you would pull out a blue marble?

Mathematics
2 answers:
777dan777 [17]3 years ago
5 0

Answer:

2 out of 6

Step-by-step explanation:

P( blue marble) = number of blue marbles / total marbles

                          = 2 /6

                     

Slav-nsk [51]3 years ago
4 0

Answer: C

Step-by-step explanation:  the reason it is c is because  the total of marbles is six  and their is only 2 marbles  so it would be 2 out of 6 you could also use process of elimination

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Step-by-step explanation:

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2(3) +5 <br> What’s the answer
stepan [7]

Answer:

11

Step-by-step explanation:

Order of Operations: BPEMDAS

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8 0
3 years ago
Read 2 more answers
Find the value of tan30+cot30+sin60​
Aliun [14]

Hello!

This is a problem about relating values of the Unit Circle.

First, we need to figure out the specific "points" of each angle measure of 30 and 60.

For the angle measure 30, the point will be (\frac{\sqrt{3}}{2},\frac{1}{2}).

For the angle measure 60, the point will be (\frac{1}{2},\frac{\sqrt{3}}{2}).

The tangent value of a point will be its y value over its x value.

\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}=\frac{1}{2}*\frac{2}{\sqrt{3}}=\frac{1}{\sqrt{3}}=\frac{\sqrt{3}}{3}

The cotangent value of a point will be the reciprocal of the tangent value, which we found previously.

\frac{3}{\sqrt{3}}=\frac{3\sqrt{3}}{3}=\sqrt{3}

The sine value of a point will be the y value of the point.

\frac{\sqrt{3}}{2}

So the values we have so far are \frac{\sqrt{3}}{3}+\sqrt{3}+\frac{\sqrt{3}}{2}

Now we have to find the LCD to add these together, which in this case would be 6.

\frac{2\sqrt{3}}{6}+\frac{6\sqrt{3}}{6}+\frac{3\sqrt{3}}{6}

Which adds up to \frac{11\sqrt{3}}{6}, which is in simplest radical form.

Hope this helps!

8 0
3 years ago
I GIVE BRAINLIEST FOR ANSWER AND EXPLANATION
MArishka [77]

i see no shaded region here

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3 years ago
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