Write 225 miles in 3 hours as a unit rate.

Amy is building a house. the basement floor is at -15 feet. the roof of the house is above the ground 25 feet. write an inequali

olchik [2.2K]

An inequation is a mathematical expression that is used to make constraints given a problem.
For example, this is a problem of heights.
There is a minimum height and a maximum height.
We can use the following inequation to describe the problem:
Let
x = height in feet.
The inequation is:
-15 <= x <= 25
answer:
-15 <= x <= 25

3 0

3 years ago

Picking a blue shirt from a drawer with 8 blue shirts and 2 white shirts.

meriva

If you dealing with probability.

You got ten shirts 8 are blue 2 are white.

So you have an 80% chance of grabbing blue and 20% of white.

And 8:2 ratio

7 0

3 years ago

8 /3 c - 2 = 2/3 c - 12 these is so hard<br><br>Solve for c. ?

cluponka [151]

Step-by-step explanation:

8 /3 c - 2 = 2/3 c - 12

Put all the one u want to solve to one side

8 /3 c - 2 = 2/3 c - 12

8/3c - 2/3c = 2-12

6/3c = - 10

Now multiply 3c to both sides

6 = - 30c

c = 6/ - 30

= 1 / - 5

= 1

- - - - - - -

5

8 0

3 years ago

Read 2 more answers

Sketch the region enclosed by x+y2=12x+y2=12 and x+y=0x+y=0. Decide whether to integrate with respect to xx or yy, and then find

Paladinen [302]

Answer:

$A = \frac{74}{3} -\frac{7}{2} +36 = \frac{127}{6} +36 = \frac{343}{6}$

Step-by-step explanation:

For this case we have these two functions:

$x+y^2 = 12$ (1)

$x+y=0$ (2)

And as we can see we have the figure attached.

For this case we select the x axis in order to calculate the area.

If we solve y from equation (1) and (2) we got:

$y = \pm \sqrt{12-x}$

$y = -x$

Now we can solve for the intersection points:

$\sqrt{12-x} = -\sqrt{12-x}$

$12-x = -12+x$

$2x=24 , x=12$

$\sqrt{12-x} =-x$

$12-x = x^2$

$x^2 +x -12=0$

$(x+4)*(x-3) =0$

And the solutions are $x =-4, x=3$

So then we have in total 3 intersection point $x=12, x=-4, x=3$

And we can find the area between the two curves separating the total area like this:

$\int_{-4}^3 |\sqrt{12-x} - (-x)| dx +\int_{3}^{12}|-\sqrt{12-x} -\sqrt{12-x}|dx$

$\int_{-4}^3 |\sqrt{12-x} + x| dx +\int_{3}^{12}|-2\sqrt{12-x}|dx$

We can separate the integrals like this:

$\int_{-4}^3 |\sqrt{12-x} dx +\int_{-4}^3 x +2\int_{3}^{12}\sqrt{12-x} dx$

For this integral $\int_{-4}^3 |\sqrt{12-x} dx$ we can use the u substitution with $u = 12-x$ and after apply and solve the integral we got:

$\int_{-4}^3 |\sqrt{12-x} dx =\frac{74}{3}$

The other integral:

$\int_{-4}^3 x dx = \frac{3^2 -(-4)^2}{2} =-\frac{7}{2}$

And for the other integral:

$2\int_{3}^{12}\sqrt{12-x} dx$

We can use the same substitution $u = 12-x$ and after replace and solve the integral we got:

$2\int_{3}^{12}\sqrt{12-x} dx =36$

So then the final area would be given adding the 3 results as following:

$A = \frac{74}{3} -\frac{7}{2} +36 = \frac{127}{6} +36 = \frac{343}{6}$

6 0

3 years ago

If the volume of a box is 1,463,000 cubic millimeters, what is the volume of the box in cubic meters? (1 millimeter = 0.001 mete

Stells [14]

Answer:

The volume of the box would be 0.001463 cubic meters

Step-by-step explanation:

You first have to to do the conversion from cubic milimiters to cubic meters using the rule given. A cubic milimiter is only 1^3 = or 1*1*1. We transform then this rule so it applies for cubic measures.

1 millimeter = 0.001 meter

(1 millimeter)^3 = (0.001 millimeter)^3 (raise to the cubic power)

1 cubic milimiter = (0.001*0.001*0.001) cubic meters= 0.000000001 or 1 * 10^-9 in scientific notation.

Then we us a rule of three as follows

1 cubic millimiter / 1 * 10^-9 cubic meters =1,463,000¨cubic milimiters / x cubic meters

x = 1,463,000*1 * 10^-9= 0.001463 cubic meters

8 0

4 years ago