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sattari [20]
3 years ago
9

Given g(x) = −3x + 4

Mathematics
1 answer:
Goshia [24]3 years ago
3 0

Answer:

The average rate of change of <em>g</em> from <em>x</em> = <em>a</em> to<em> x</em> = <em>a</em> + <em>h</em> is -3.

Step-by-step explanation:

We are given the function:

g(x) = -3x + 4

And we want to determine its average rate of change of the function for <em>x</em> = <em>a</em> and <em>x</em> = <em>a</em> + <em>h</em>.

To determine the average rate of change, we find the slope of the function between the two points. In other words:

\displaystyle \text{Avg} = \frac{g(a + h) - g(a) }{(a + h ) - a}

Simplify:

\displaystyle \begin{aligned}  \text{Avg} &= \frac{g(a + h) - g(a) }{(a + h ) - a} \\ \\ &=\frac{(-3(a+h) + 4) - (-3a+4)}{h} \\ \\ &= \frac{(-3a -3h + 4) + (3a - 4) }{h} \\ \\ &= \frac{-3h}{h} \\ \\ &= -3\end{aligned}

In conclusion, the average rate of change of <em>g</em> from <em>x</em> = <em>a</em> to <em>x</em> = <em>a</em> + <em>h</em> is -3.

This is the expected result, as function <em>g</em> is linear, so its rate of change would be constant.

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Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π    →     C = π - (A + B)

                                    → sin C = sin(π - (A + B))       cos C = sin(π - (A + B))

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Use the following Sum to Product Identity:

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Use the following Double Angle Identity:

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<u>Proof LHS → RHS</u>

LHS:                        (sin 2A + sin 2B) + sin 2C

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\text{Given:}\qquad \qquad \quad 2\sin C\cdot \cos (A - B)+2\sin C\cdot \cos (A+B)

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\text{Sum to Product:}\qquad 2\sin C\cdot 2\cos A\cdot \cos B

\text{Simplify:}\qquad \qquad 4\cos A\cdot \cos B \cdot \sin C

LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C    \checkmark

7 0
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8 0
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