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Artist 52 [7]
3 years ago
12

NEED HELP ON MATH. CLICK HERE.

Mathematics
1 answer:
Sonbull [250]3 years ago
7 0
Its c because 11/10 gives you a whole number
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If you start a free trial without a form of payment attached to your account can you get charged by the website?
natka813 [3]

Don't think so.

/ᐠ。ꞈ。ᐟ\

*Has to add more words to be able to answer this*

8 0
3 years ago
Read 2 more answers
The profits in hundreds of dollars, P(c), that a company can make from a product is modeled by a function of the price, c, they
Valentin [98]

Answer:

6400

Step-by-step explanation:

Given the profit function ;

P(c) = –20c2 + 320c + 5,120

The maximum value is given by :

f(h) ; where, h = - b /2a

From P(C) ; a = - 20 ; b = 320

h = - b / 2a = - 320 / 2(-20) = - 320 / 40 = 8

c = h

P(8) = –20(8)² + 320(8) + 5,120

P(8) = - 1280 + 2560 + 5120

= 6400

4 0
3 years ago
How much fabric is needed to create the lateral faces of the tent?
jek_recluse [69]
Left and right side: 6.4*7=44.8
44.8+44.8=89.6
front (where the zipper is) and back: half of 5*8=20
20+20=40

40+89.6=129.6

the area of the bottom is 7*8=56

the total area is 129.6+56=185.6

I am not sure what lateral area includes. To me, the answer should be 129.6, but 129.6 is not a choice. 
I'd suggest 185.6, the total surface area. 
7 0
3 years ago
Which of the following is a trinomial with a constant term O A. -x + y10 O B. x3 + 11x2 + x O C. x + 4y+ 7 O D.​
Kamila [148]

Answer:

<h2><em><u>C. x + 4y+ 7</u></em></h2>

Step-by-step explanation:

As,

In it there are three different terms x, 4y and 7 hence a trinomial, then there is a constant term 7.

5 0
3 years ago
Read 2 more answers
Polly stacked the tins from five boxes of cat food onto an empty shelf in a supermarket. There were 15 tins of cat food in each
Alexandra [31]

Answer:

(a) 3\frac{2}{3} boxes of cat food had been sold.

(b) \frac{11}{3} boxes of cat food had been sold.

Step-by-step explanation:

From the question,

Polly stacked the tins from five boxes of cat food onto an empty shelf and there were 15 tins of cat food in each box. That is,

5 × 15 tins of cat food were stacked onto the empty shelf.

5 × 15 = 75

Hence, 75 tins of cat food were stacked onto the empty shelf.

Also, from the question,

At the end of the week there were 20 tins left on the shelf and the rest of the tins had been sold, that is

75 - 20 tins had been sold

75 - 20 = 55

Hence, 55 tins of cat food had been sold.

To determine the number of boxes of cat food that had been sold,

Since there are 15 tins of cat food per box, then

we will divide 55 tins of cat food that had been sold by 15 tins of cat food per box

55 ÷ 15 = \frac{55}{15}

Hence, \frac{55}{15} boxes of cat food had been sold

(a) As a mixed number

\frac{55}{15}  = 3\frac{2}{3}

Hence, 3\frac{2}{3} boxes of cat food had been sold.

(b) As an improper fraction

\frac{55}{15}  = \frac{11}{3}

Hence, \frac{11}{3} boxes of cat food had been sold.

7 0
3 years ago
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