Show me how 3/6 are equivalent fraction to 1/2

Mathematics

1 answer:

g100num [7]3 years ago

6 0

You can divide the numerator and the denominator by 3, which would give you ½.

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Crank

Sounds like an id 10 t problem

5 0

3 years ago

Three fifths of one sixths evaulate expression

sukhopar [10]

3/5 of 1/6 is written as

3/5 x 1/6

Multiply both the numerator and denominators together:

3x1 / 5*6 = 3/30, reduces to 1/10.

The answer is 1/10.

3 0

3 years ago

Read 2 more answers

Question 5 (1 point)

ElenaW [278]

Answer:

The volume of the shape is 560 ft^3

Step-by-step explanation:

To find the volume of the figure, we need to multiply the base area by the height of the figure

mathematically, we have the base area as a rectangular shape and its area is the product of its side lengths

We have this as 8 ft * 10 ft = 80 ft^2

So multiplying this by the height which is 7 ft, we have this as;

7 ft * 80 ft^2 = 560 ft^3

3 0

3 years ago

Solving linear system, substitution 20x-30y=-50 x+2y=1 HELP PLEASE

hjlf

20x - 30y = -50 ⇒ 20x - 30y = -50
 x + 2y = -1 ⇒ 20x + 40y = -20
 -70y = -30
 -70 -70
 y = ³/₇
 20x - 30(³/₇) = -50
 20x - 12⁶/₇ = -50
 + 12⁶/₇ + 12⁶/₇
 20x = 47¹/₇
 20 20
 x = 2⁷/₂₀
 (x, y) = (2⁷/₂₀, ³/₇)

6 0

3 years ago

Taylor's computer randomly generate numbers between 0 and 4, as represented by the given uniform density curve.

MrRa [10]

12.5% is the percentage of numbers randomly generated by Taylor's computer that is less than 0.5.

An illustration of a numerical distribution with continuous results is a density curve. A density curve is, in other words, the graph of a continuous distribution. This implies that density curves can represent continuous quantities like time and weight rather than discrete events like rolling a die (which would be discrete). As seen by the bell-shaped "normal distribution," density curves either lie above or on a horizontal line (one of the most common density curves).

The percentage of numbers randomly generated by Taylor's computer are less than 0.5 is given by

P(0≤X≤0.5)

= $\int_{0}^{0.5}\frac{1}{4}dx$