Supposing a spinner with 4 sides, the sample space is:
{H1, H2, H3, H4, T1, T2, T3, T4}
The sample space is the <u>set that contains all possible outcomes for an experiment</u>.
In this problem:
- For the coin, there are two possible outcomes: H or T.
- Supposing the spinner has 4 sides, there are four possible outcomes: 1, 2, 3, or 4.
Hence, the sample space is:
{H1, H2, H3, H4, T1, T2, T3, T4}
For more on sample space, you can check brainly.com/question/25775544
-y² +13x + 3y - 3
is your answer
hope this helps
Answer:
Choice B is correct; the domain of function A is the set of real numbers greater than 0
The domain of the function B is the set of real numbers greater than or equal to 1
Step-by-step explanation:
The domain of a function refers to the set of x-values for which the function is real and defined. The graph of function B reveals that the function is defined when x is equal 1 and beyond; that is its domain is the set of real numbers greater than or equal to 1.
On the other hand, the natural logarithm function is defined everywhere on the real line except when x =0; this will imply that its domain is the set of real numbers greater than 0 . In fact, the y-axis or the line x =0 is a vertical asymptote of the natural log function; meaning that its graph approaches this line indefinitely but neither touches nor crosses it.
36 cm^2
Step-by-step explanation:
<u>Small</u><u> </u><u>window</u>
Length: 2cm
Width: 2cm
<u>Area</u><u>:</u> 4 cm^2
<u>Big window</u>
Length: 4cm
Width: 3cm
<u>Area</u><u>:</u> 12 cm^2
Total area of the windows:
(Area of 4 small windows + area of 1 big window)
(4 cm^2 x 4 + 12cm^2)
= <u>28 cm^2</u>
<u>Above</u><u> </u><u>window</u><u> </u><u>(</u><u>approx</u><u>.</u><u>)</u>
<u>Rectangle</u>
Length: 3cm
Width: 2cm
<u>Area</u><u>:</u> 6 cm^2
<u>T</u><u>riangle</u>
Base: 1cm
Height: 1cm
<u>Area</u><u>:</u> 2 x 0.5 cm^2 = 1 cm^2
<u>Square</u><u> </u><u>(</u><u>between</u><u> </u><u>the</u><u> </u><u>triangles</u><u>)</u>
Length: 1cm
Width: 1cm
<u>Area</u><u>:</u> 1 cm^2
= 8 cm^2
<u>TOTAL</u><u> </u><u>AREA</u><u> </u><u>OF</u><u> </u><u>ALL</u><u> </u><u>WINDOWS</u>
= AREA OF 4 WINDOWS + AREA OF BIG WINDOW + AREA OF ABOVE WINDOW
= 16 cm^2 + 12 cm^2 + 8 cm^2
<h3>
= <u>
36 cm^2</u></h3>
<em>I</em><em> </em><em>hope</em><em> </em><em>I</em><em> </em><em>made</em><em> </em><em>the</em><em> </em><em>explanations</em><em> </em><em>clear</em><em> </em><em>enough</em><em> </em><em>to</em><em> </em><em>make</em><em> </em><em>it</em><em> </em><em>easier</em><em> </em><em>for</em><em> </em><em>you</em><em> </em><em>to</em><em> </em><em>understand</em><em>!</em>
Answer:
Step-by-step explanation:
Step: 1: Convert mixed fraction to improepr fraction.
Step: 2 : Find the LCM of 4 , 5 = 20
Step 3: Find equivalent fractions with denominator as 20
Step 4: Now subtract.
