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andreev551 [17]
4 years ago
11

What is the length of MN

Mathematics
1 answer:
Irina-Kira [14]4 years ago
6 0

Answer: D. 4

Step-by-step explanation:

In the given picture , we have given a triangle ΔMLN in which

ML= 4x and MN= x+3

∠L=∠N=50°

⇒ MN=ML   [∵ Basically by Isosceles triangle property :sides opposite to equal angles of a triangle area equal.]

\Rightarrow\ x+3=4x

Subtract x from both sides , we get

3=3x

Divide bothe sides by x , we get

1= x  or x =1

Then, the length of MN = x+3=1+3=4 units

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Jin is training for the 50 meter dash. Each day that he trains, he runs the dash six times. Last week, he trained for four days.
iragen [17]

Answer:

1 1/2 kilometers

Step-by-step explanation:

If he runs 3000 meters every day and then trains for 5 days that means he ran 1 1/2 kilometers

3 0
3 years ago
if i had 100 cookies and my friend has 50, but he took 50 more from me, and now i have 150 cookies and a dead body how many dead
Svetlanka [38]

Answer:

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Step-by-step explanation:

8 0
3 years ago
What values of x satisfy the equation 2x^2 -3x +4 =0
BaLLatris [955]

Answer:

(3 ± √23 * i) /4

Step-by-step explanation:

To solve this, we can apply the Quadratic Equation.

In an equation of form ax²+bx+c = 0, we can solve for x by applying the Quadratic Equation, or x = (-b ± √(b²-4ac))/(2a)

Matching up values, a is what's multiplied by x², b is what's multiplied by x, and c is the constant, so a = 2, b = -3, and c = 4

Plugging these values into our equation, we get

x = (-b ± √(b²-4ac))/(2a)

x = (-(-3) ± √(3²-4(2)(4)))/(2(2))

= (3 ± √(9-32))/4

= (3 ± √(-23))/4

= (3 ± √23 * i) /4

6 0
3 years ago
Need help with this question
tatuchka [14]
Z(x)=6x^3+19x^2-52x+15
(6*-5)^3+19*-5^2-52*-5+15
Z(x)= -17,700
4 0
4 years ago
Solve for c: 6/15=2/c
Xelga [282]
6/15 = 2/c
6/3 = 2, therefore you must divide 15 by 3 to get 5. c = 5
6/15 = 2/5
6 0
4 years ago
Read 2 more answers
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