<u>Answer:</u>
The equation using a fractional exponent
is 
<u>Solution:</u>
Given, term is cube root of x square
In numerical terms cube root of x square can be written as ⇒ cube root of ![x^{2} \rightarrow \sqrt[3]{x^{2}}](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%5Crightarrow%20%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%7D)
We have to write the expression for above given term in the form of fractional exponent of x.
In
, cube root is written in fractional form

Now, powers are multiplied


Finally x is in power of a fraction, so we got the required answer
Answer:
You turn the whole number into a fraction by putting the dominator as 1 and numerator as 3. Multiple 3 and 5 so straight across.
Answer:
270 uits
Step-by-step explanation:
Answer:
(- 2, 15 ) and (2, 7 )
Step-by-step explanation:
Given the 2 equations
y = 3x² - 2x - 1 → (1)
2x + y = 11 → (2) ← subtract 2x from both sides
y = 11 - 2x → (3)
Substitute y = 3x² - 2x - 1 into (3)
3x² - 2x - 1 = 11 - 2x ( subtract 11 - 2x from both sides )
3x² - 12 = 0 ( add 12 to both sides )
3x² = 12 ( divide both sides by 3 )
x² = 4 ( take the square root of both sides )
x = ±
= ± 2
Substitute these values into (3) for corresponding values of y
x = - 2 : y = 11 - 2(- 2) = 11 + 4 = 15 ⇒ (- 2, 15 )
x = 2 : y = 11 - 2(2) = 11 - 4 = 7 ⇒ (2, 7 )