I will determine the log base 2 of x for the x-values in the set {1, 2, 4, 8, 16}.
I will use these properties:
log base m of m^n = n,
Which written with the math editor is:
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1) x = 1
1 = 2^0 =>

2) x = 2
2 = 2^1 =>

3) x = 4
4 = 2^2 =>

4) x = 8
8 = 2^3 =>

5) x = 12
16 = 2^4 =>

6) Now you can plot the points on the graph. The points that you have to plot are:
(1,0)
(2,1)
(4,2)
(8,3)
(16,4)
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<span>So we want to know the new coordinates for the vertex A'(x,y) if we know that the vertex A is at A(-1,2) and vertex B is at B(1,5) and that the triangle ABC is translated 6 units up and 3 units left. So the method is simply to add units 6 to x and 3 to y of A to get A'. Going left means we need to go to negative x direction and going up means we need to go to positive y direction. So: A'(-1-3,2+6) and that is: A'(-4,8). </span>
Answer:
derek bought 8.5 more yards of fabric
Step-by-step explanation: