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Advocard [28]
3 years ago
9

There are 50 seashells on the beach after one week there are 120 seashells on the beach if this continues the same patterns how

many seashells will there be on the 4th week
Mathematics
2 answers:
e-lub [12.9K]3 years ago
5 0

Answer:

120

×4

480

+50

530

Step-by-step explanation:

miskamm [114]3 years ago
3 0

Answer:

Impossible to know from facts given. Maybe 192 or 320

Step-by-step explanation:

The difference between the original number, 50 and the week later 120 is 70

One way to predict the following two weeks might be to look at the the <u>difference</u> between the first deposit and the second deposit and predict that the <u>amount added</u> will increase by the same amount. That difference is 20.

50 + 70 + 90 + 110 = 320.

Another way is to look at the percentage of the increase and use that rate to predict the subsequent deposits,

The increase from the first week to the second week is 70/50. That is 1.4 or an increase of 140%. If that <u>rate </u> continues, the amounts are different.

50 x 1.4 = 70   70 x 1.4 = 98  98 x 1.4 = 137.2  137.2 x 1.4 = 192.08

This entire problem is suspect! There is no punctuation. And who can ensure that the beach won't be disturbed by a storm that washes away the shells or beachcombers who collect them?

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Step-by-step explanation:

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2 years ago
A random sample of 200 people was taken. 90 of the people in the sample favored Candidate A. We are interested in determining wh
mafiozo [28]

Answer:

a. 1.44

Step-by-step explanation:

We are interested in determining whether or not the proportion of the population in favor of Candidate A is significantly more than 40%.

At the null hypothesis, it is tested if the proportion is of at most 40%, that is:

H_0: p \leq 0.4

At the alternative hypothesis, it is tested if the proportion is of more than 40%, that is:

H_1: p > 0.4

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.4 is tested at the null hypothesis:

This means that p = 0.4, \sigma = \sqrt{0.4*0.6}

A random sample of 200 people was taken. 90 of the people in the sample favored Candidate A.

This means that:

n = 200, X = \frac{90}{200} = 0.45

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.45 - 0.4}{\frac{\sqrt{0.4*0.6}}{\sqrt{200}}}

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3 years ago
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Why....

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jek_recluse [69]

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3 years ago
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