Please help pleaseeeeeeee

Mariana [72]

The answer is 4. You take 2 and divide it by 0.5.

3 0

2 years ago

There are 1,295 students attending a small university.There are 714 women enrolled. What percent of the students are women. Equa

Semenov [28]

If 1295 × p = 714, then you can rearrange the equation to find the percentage.

You have to get p on its own, so you divide 1295 on both sides of the '='.

1295 × p = 714

p = 714 ÷ 1295

p = <span>0.55135135135...

p </span>× 100 = actual percentage

actual percentage = 55.14%

8 0

2 years ago

One half of the sum of a number and 10

garri49 [273]

Let's assume the number be x.

So, sum of a number and 10 can be written as x+10.

Now the given statement is "One half of the sum of a number and 10 ".

So, one half of x+10 can be written as $\frac{1}{2} (x+10)$

6 0

3 years ago

A college bookstore marks up the price that it pays the publisher for a book by 35 %. If the selling price of a book is $ 87.00

Dimas [21]

Answer:the amount that the bookstore pay the publisher for the book is $64.4

Step-by-step explanation:

Let x represent the amount that the bookstore pay the publisher for the book.

The college bookstore marks up the price that it pays the publisher for a book by 35%. This means that the value of the mark up would be

35/100 × x = 0.35 × x = 0.35x

Therefore, the amount that the bookstore is selling the book would be

x + 0.35x = 1.35x

If the selling price of a book is $ 87.00, then it means that

1.35x = 87

x = 87/1.35 = 64.4

7 0

3 years ago

Suppose that a fast food restaurant decides to survey its customers to gauge interest in a breakfast menu. After surveying multi

Harlamova29_29 [7]

Answer:

$ME= \frac{Width}{2}=\frac{0.078}{2}=0.039$

$\hat p =0.688+0.039=0.727$

$\hat p =0.766-0.039=0.727$

Step-by-step explanation:

Assuming that the confidence interval is (0.688; 0.766)

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

Use the confidence interval to find the point estimate and margin of error for the proportion

The margin of error is given by :

$Me=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And for our case we can find the width of the confidence interval like this:

Width =0.766-0.688=0.078

And the estimation for the margin of error would be given by:

$ME= \frac{Width}{2}=\frac{0.078}{2}=0.039$

Now we can find th point of estimate adding the margin of error to the lower limit of the interval or subtracting the margin of error to the upper limit, like this:

$\hat p =0.688+0.039=0.727$

$\hat p =0.766-0.039=0.727$

4 0

3 years ago

Please help pleaseeeeeeee ​

Please help pleaseeeeeeee