This involves quite a lot of arithmetic to do manually.
The first thing you do is to make the first number in row 2 = to 0.
This is done by R2 = -3/2 R1 + R2
so the matrix becomes
( 2 1 1) ( -3 )
( 0 -13/2 3/2) (1/2 )
(5 -1 2) (-2)
Next step is to make the 5 in row 5 = 0
then the -1 must become zero
You aim for the form
( 1 0 0) (x)
(0 1 0) (y)
(0 0 1) ( z)
x , y and z will be the required solutions.
15x12=180
180$ simple unless u have a different way to do it
Answer:
-4(8-3x)>or =6x-8
Step-by-step explanation:
open d bracket
-32+12x >or = 6x-8
collect like terms
12x-6x >or =-8+32
6x = 24
divide both sides by 6
x= 4
Answer:
x = 4
y = -2
Step-by-step explanation:
x + 10y = -16
-x -4y = 4 <-- ( multiplied x+4y=-4 with -1 so the x's cancel)
6y = -12
y = -2
put -2 back in the equation to get x
x + 10y = -16
x -20 = -16
x = 4