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Lelu [443]
3 years ago
5

Anyone help!!!! Please I grant brainliest.

Mathematics
2 answers:
lakkis [162]3 years ago
7 0

Answer:

hope this helps you.........

Masja [62]3 years ago
4 0

Length of arc = 11 cm

Answer:

Area of sector =115.5 square cm

Step-by-step explanation:

Length of arc =  \frac{30 \degree}{360 \degree}  \times 2 \times  \frac{22}{7}  \times 21 \\  \\  = \frac{1}{12}  \times 2 \times  22  \times 3 \\  \\  = \frac{1}{12}  \times 6 \times  22\\  \\  = \frac{1}{2}  \times  22\\  \\  = 11 \: cm \\  \\  \\  \\ area \: of \: sector =  \frac{ 30 \degree}{360 \degree}  \times \pi {r}^{2}  \\  \\  =  \frac{1}{12}  \times  \frac{22}{7}  \times  {21}^{2}  \\  \\  =  \frac{1}{12}  \times  \frac{22}{7}  \times 21 \times 21 \\  \\  = 115.5 \:  {cm}^{2}  \\

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In a student body, 50% use Google Chrome, 9% use Internet Explorer, 10% Firefox, 5% Mozilla, and the rest use Safari. In a group
Likurg_2 [28]

Answer:

The probability that exactly 1 student is using Internet Explorer and at least 3 students are using Chrome is 0.1350.

Step-by-step explanation:

Denote the events as follows:

<em>C</em> = a student uses Google chrome

<em>E</em> = a student uses Internet explorer

<em>F</em> = a student uses Firefox

<em>M</em> = a student uses Mozilla

<em>S</em> = a student uses Safari

Given:

P (C) = 0.50

P (E) = 0.09

P (F) = 0.10

P (M) = 0.05

P (S) = 0.26

A sample of <em>n</em> = 5 students is selected.

The probability that exactly 1 student is using Internet Explorer and at least 3 students are using Chrome is:

P (E = 1 ∩ C ≥ 3) = P (E = 1 ∩ C = 3) + P (E = 1 ∩ C = 4) - P (E = 1 ∩ C = 5)

The probability distribution of a student using any of the browser is Binomial.

Compute the probability that exactly 1 student is using Internet Explorer and at least 3 students are using Chrome as follows:

P (E = 1 ∩ C ≥ 3) = P (E = 1 ∩ C = 3) + P (E = 1 ∩ C = 4) - P (E = 1 ∩ C = 5)

                          = P (E = 1) [P (C = 3) + P (C = 4) - P (C = 5)]

       ={5\choose 1}(0.09)^{1}(1-0.09)^{5-1}[{5\choose 3}(0.50)^{3}(1-0.50)^{5-3}+{5\choose 4}(0.50)^{4}(1-0.50)^{5-4}\\-{5\choose 5}(0.50)^{5}(1-0.50)^{5-5}]\\=0.3086[0.3125+0.1563-0.0313]\\=0.3086\times 0.4375\\=0.1350

Thus, the probability that exactly 1 student is using Internet Explorer and at least 3 students are using Chrome is 0.1350.

5 0
3 years ago
Solve the equation 2x +45 = 9. Explain the steps<br> and properties you used.
timurjin [86]

Answer:

Step-by-step explanation:

Here you go mate

Step 1

2x+45=9  Equation/Question

Step 2

2x+45=9  Simplify

Step 3

2x+45=9  Subtract 45 from sides

2x=-36

Step 4

2x=-36  Divide sides by 2

-18

Answer

x=-18

Hope this helps

7 0
2 years ago
Read 2 more answers
Which expression is equivalent to ^4√16x^11y^8/81x^7y^6 ? Assume x &gt; 0 and y = 0
ollegr [7]
<span> For this case we have an expression of the form:
</span> \sqrt[4]{16x^{11}y^8}/(81x^7y^6)
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 Rewriting the expression we have:
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 Then, by root properties we have:
 2x^2y^2(\sqrt[4]{x^3})/(81x^7y^6)&#10;
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 Answer: 
 An <span>expression that is equivalent is:
</span> 2(\sqrt[4]{x^3})/(81x^5y^4)
  
3 0
3 years ago
How do you write a verbal expression for p4 +6r?
serious [3.7K]
A number times 4 plus 6 times another number.
4 0
3 years ago
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Which statement about a system of linear equations is incorrect?
lana [24]
The answer might be c
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2 years ago
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