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sergey [27]
4 years ago
10

rasheed wants to buy two new video games that cost 28.50 each he earns money for them by mowing lawns in his neighborhood and hi

s earnings are shown in the tablebelow how much more money does rasheed need to earn before he can buy the video games
Mathematics
1 answer:
VashaNatasha [74]4 years ago
4 0

Answer: $15.25

Step-by-step explanation:

When you multiply 28.50 times two gives you 57, all the amounts earned (7.50,4.85,12.25,9.00,8.15) gives you 41.75 subtract 57 from 41.75 , that give you 15.25. Hope this helps.

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Dmitry_Shevchenko [17]

Answer:

a_{10} = \frac{10}{65536}

Step-by-step explanation:

The first step to solving this problem is verifying if this sequence is an arithmetic sequence or a geometric sequence.

This sequence is arithmetic if:

a_{3} - a_{2} = a_{2} - a_{1}

We have that:

a_{3} = 40, a_{2} = 10, a_{3} = \frac{5}{2}

a_{3} - a_{2} = a_{2} - a_{1}

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This sequence is geometric if:

\frac{a_{3}}{a_{2}} = \frac{a_{2}}{a_{1}}

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\frac{5}{20} = \frac{1}{4}

\frac{1}{4} = \frac{1}{4}

This is a geometric sequence, in which:

The first term is 40, so a_{1} = 40

The common ratio is \frac{1}{4}, so r = \frac{1}{4}.

We have that:

a_{n} = a_{1}*r^{n-1}

The 10th term is a_{10}. So:

a_{10} = a_{1}*r^{9}

a_{10} = 40*(\frac{1}{4})^{9}

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Simplifying by 4, we have:

a_{10} = \frac{10}{65536}

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Answer:

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