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3 years ago

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A group of friends went out for dinner and decided to split the cost of the $196 bill equally. If each person contributed $30, t

hey would not have enough to leave a 15% tip. But if each person contributed $33, they would cover the bill and a 15% tip and have $5.60 left over. How many friends went out to dinner? 1 point

1 answer:

IgorLugansk [536]3 years ago

7 0

Answer:6 friends

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A metal bar weighs 9.25 ounces. 65% of the bar is gold. how many ounces of gold is in the bar?

Elza [17]

Not sure I'm right but:

If the bar weighs 9.25 ounces and 65% of the bar is gold, you'd do 65% of 9.25. So the answer would be <span>65% of 9.25= 6.0125</span>

6 0

3 years ago

Reptile [31]

Answer:

The real zeros of f(x) are x = 0.3 and x = -3.3.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this problem, we have that:

$f(x) = x^{2} + 3x - 1$

So

$a = 1, b = 3, c = -1$

$\bigtriangleup = 3^{2} - 4*1*(-1) = 13$

$x_{1} = \frac{-3 + \sqrt{13}}{2*1} = 0.3$

$x_{2} = \frac{-3 - \sqrt{13}}{2*1} = -3.3$

The real zeros of f(x) are x = 0.3 and x = -3.3.

7 0

3 years ago

A tire has a diameter of 184 cm what is the circumference of the tire

viktelen [127]

Here is your answer

diameter of tyre= 184cm

So,

Circumference= $\:{pi}$ ×d

= 3.14 × 184 cm

= 577.76 cm

HOPE IT IS USEFUL

8 0

3 years ago

Use Pythagorean Theorem to solve for x.<br><br> HELP ME PLZZZZ!!!! ASAP

4vir4ik [10]

Answer: $2\sqrt{22}$

Step-by-step explanation:

Pythagorean theorem: $a^{2} +b^{2} = c^{2}$ , where a and b are the legs and c is the hypotenuse.

We can solve for x by only using the left side of the triangle. Since we're only using the left side of the triangle, we can reduce 18 by 2 to get 9. Now we plug in our information to the equation.

$9^{2} +b^{2} = 13^{2}$

$81 +b^{2} = 169$

Since we don't know what $b^{2}$ is, we're going to isolate it by subtracting 81 on both sides

$b^{2} = 88$

We have to square root both sides in order to find out b (or x in the problem).

$\sqrt{b^{2}} = \sqrt{88}$

When you put this on a calculator it would result in $2\sqrt{22}$ which is the answer d in the problem.

6 0

3 years ago

2. A square-based tent has the cross-sectional

ollegr [7]

(a) Length of the height is 2.732 m

(b) Length of the base is 5.466 m

<u>Explanation:</u>

An image is attached for reference.

(a)

In ΔAOB,

$sin 30^o = \frac{AO}{AB} \\\\0.5 = \frac{AO}{2} \\\\AO = 1 m$

In ΔBGD,

$sin 60^o = \frac{BG}{BD} \\\\0.866 = \frac{BG}{2} \\\\BG = 1.732 m$

According to the figure, BG = OE = 1.732 m

Height of the tent, AE = AO + OE

= 1 m + 1.732 m

= 2.732 m

(b)

DF = ?

In ΔAOB,

$tan 30^o = \frac{AO}{OB} \\\\0.577 = \frac{1}{OB} \\\\OB = 1.733 m\\\\\\$

According to the figure, OB = GE = 1.733 m

In ΔBGD,

$tan 60^o = \frac{BG}{DG} \\\\1.732 = \frac{1.732}{DG}\\ \\DG = 1m$

According to the figure, DE = DG + GE

DE = 1 m + 1.733 m

DE = 2.733 m

Length of the base, DF = 2 X DE

DF = 2 X 2.733 m

DF = 5.466 m

8 0

3 years ago