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Olegator [25]
3 years ago
10

What value must be defined for to remove the discontinuity of this function at ?

Mathematics
1 answer:
olchik [2.2K]3 years ago
4 0

Answer:

Option D. 8

Step-by-step explanation:

we have

f(x)=\frac{x^{2}-16 }{x-4}

Remember that

x^{2}-16 =(x+4)(x-4)

substitute

f(x)=\frac{(x+4)(x-4)}{x-4}

Remove the discontinuity at x=4

Simplify

f(x)=(x+4)

so

Find the value of f(4)

For x=4

f(4)=(4+4)=8

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