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nignag [31]
3 years ago
8

Name two obtuse angles in the shape below

Mathematics
1 answer:
Wewaii [24]3 years ago
5 0
Is there supposed to be a picture to this question
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Mariylnn is going to paint a wall in her bedroom. The wall is 15 feet long and 8 feet tall. The window takes up an area 6 feet l
USPshnik [31]

Answer:

96 square feet

Step-by-step explanation:

What we need to do here, is find the total area of Mariylnn's wall, and subtract the area of her window from that.

Area of wall:

15*8=120

Area of window:

4*6=24

Area of wall without window:

120-24=96

8 0
3 years ago
What is 3/2y - 3 + 5/3z when y= 6 and z = 3
kirill [66]

Answer:

-2.195

Step-by-step explanation:

Substitute the given values of y and z to the equation

= 3/2y-3+5/3z

= 3/2(6) - 3 + 5/3(3)

= 3/12 - 3 + 5/9

In order to easily solve the equation, we change the fractions into decimals.

3/12 = 0.25

5/9 = 0.555

= 0.25 - 3 + 0.555

= - 2.195

7 0
2 years ago
Read 2 more answers
Solve and then use estimation to make sure your answer is reasonable.
Vinil7 [7]
114.5 hours = 6870 minutes
∴ 6870 ÷ 22 = 312.2727273
3 0
3 years ago
Food allergies affect an estimated 7% of children under age 5 in the US. What is the probability that in a kindergarden class of
bezimeni [28]

Answer:

Probability of atleast one of 12 student has food allergies ≈ 0.58 ( approx)

Step-by-step explanation:

Given: Probability of a children under age 5 has food allergies = 7%

                                                                                                        =\frac{7}{100}

To find : Probability of atleast one of 12 student has food allergies

Probability of a chindren under age 5 does not have food allergies = 1-\frac{7}{100}

                  ⇒ prob = \frac{93}{100}

now we find Probability of atleast one of 12 student has food allergies this means we have to find prob of 1 student, 2 student, 3 student, till 12 student have allergy out of 12 student of class then add all prob.

But instead of finding all these probability we find probability of student having no allergy.i.e., 0 student then subtract it from 1(total probability)

Probability of 0 student having allergy out of 12 student = (\frac{93}{100})^{12}

Therefore, Probability of atleast one of 12 student has food allergies

                  = 1-(\frac{93}{100})^{12}

                  = 0.581403702521

                  ≈ 0.58 ( approx)

                 

8 0
3 years ago
Read 2 more answers
The question I need help on is 15.5z= -77.5 . I really don't get it please help:)
melamori03 [73]
The answer to this question is z=-5 
6 0
3 years ago
Read 2 more answers
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