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docker41 [41]
3 years ago
5

Will give brainliest and more. 30 points. A cell phone company charges $40 plus $15 per line each month. Jake must spend less th

an $115 on his family's cell phone bill each month. How many cell phones can his family have?
Mathematics
2 answers:
amid [387]3 years ago
8 0

Answer:

the answer is 5 lines

Step-by-step explanation:

the equation would be

y= 40 + 15x

in this case y is $115

so that leaves you with:

115= 40 + 15x

115- 40 = 15x

75 = 15x

75/15 = 15/15x

5= x

kolbaska11 [484]3 years ago
4 0

they can have 5 cell phones.

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The first floor of a house consists of a kitchen, playroom, and dining room. The areas of the kitchen, playroom, and dining room
lozanna [386]

Answer: See explanation

Step-by-step explanation:

From the question, we are informed that the areas of the kitchen, playroom, and dining room are in the ratio 4 : 3 : 2 and that the combined area of these three rooms is 189 square feet.

Therefore, Kitchen area = 4/(4+3+2) × 189 = 4/9 × 189 = 84 square feet

Playroom area = 3/(4+3+2) × 189 = 3/9 × 189 = 63 square feet

Dining room area = 2/(4+3+2) × 189 = 2/9 × 189 = 42 square feet

5 0
3 years ago
A system of equations is graphed on the coordinate plane.
konstantin123 [22]
The solution appears to be (-2,0)
4 0
4 years ago
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F.<br> x4 + 2x3 +6x² + 4x+8 by x2 +2.
Anna71 [15]

Answer:

explain correctly please

5 0
3 years ago
Please help! I will give 5 star rating and brainlest ! To anyone that helps with this question
kiruha [24]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Can someone please help me factor 6x^2 - 9x+42
frutty [35]

Answer:

3(2x^2-3x+14)

Step-by-step explanation:

6x^2-9x+42

All three terms have a common factor of 3

3(2x^2-3x+14)

Now let's focus on 2x^2-3x+14 and bring down the factor 3 later

so a=2

b=-3

c=14

Let's try to find two factors for ac that multiply to be a*c and add up to be b.

ac=28

b=-3

-----

ac=7(4)=14(2)=8(2)

Even if I made these pairs with both negatives nothing would give me -3

So you can only go as far as 3(2x^2-3x+14)

Here is another thing to help you if you have ax^2+bx+c and b^2-4ac<0 then it can't be factored (over reals)

6 0
3 years ago
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