Easy just ask me I know everything
To solve this problem, we have to figure out a rule for the function. We are told that it is a two-step rule, so it is most likely the input multiplied by a coefficient plus a constant. Let’s let the input be represented by the variable x and the output be represented by the variable y. Using our knowledge, we can see that the outputs are close to triple the input, so we set up the preliminary equation:
y = 3x + b,
where b is a constant. If we want to solve for b, we must plug in one of our input/output pairs. If we plug in (5,16), we get the following:
16 = 3(5) + b
16 = 15 + b
1 = b
Then, we should substitute in this value into our equation and check our work.
y = 3x + 1
If we plug in the other points, this equation yields a true statement, so we know it is correct.
Hope this helps!
I think the answer is
0.32
Answer:
79% - almost 4 times out of 5.
The key to this is realizing that the number of games will not always be 5.
If A wins in a sweep - you have 2/3*(2/3)*2/3 percent chance of that happening - 8/27, or 29.63%
If A wins in 4, now we have 2/3*(2/3)*2/3*(1/3)*3 - the 1/3 is the chance that B wins a game. Note - there are only 3 ways B can win a game, not 4. B cannot win Game 4 because Game 4 would not be played in case of a sweep. That is why you cannot use a straight Pascal’s triangle to get your coefficients - the 1–4–6–4–1 is not possible if B cannot win Game 4. Anyway, the math is the same as the above, a 29.63% chance of A winning in 4.
For a 5 game set, A could lose 2 games in 6 possible ways (lose 1&2, 1&3, 1&4, 2&3, 2&4 or 3&4). Again, A cannot lose Game 5 - it would not be played once A wins 3 games. So the odds become 2/3*(2/3)*2/3*(1/3)*(1/3)*6, or 19.75%.
Add them up and you get 79.01%
Step-by-step explanation:
Hope it helps<3
