Answer:
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I hope it helped if you have any further questions you can ask
Answer:
1.No
2.No
3.Transitive
Step-by-step explanation:
We are given that a relation
{(0,0),(0,1),(0,2),(1,2)}
If a relation is reflexive then (a,a) belongs to relation for each a belongs to given set.
A relation is symmetric
If (a,b) then,
A relation is transitive
(a,b) and (b,c) then, (a,c)
1.The relation is not reflexive because (1,1) does not belongs to
2.The relation is not symmetric because (2,0)
3.It is transitive because (0,1) and (1,2) then (0,2)[tex\in R_3[/tex]
OK.
Then the other number is anything that's less than -9 or more than 15 .
Cubing of integers from 1 to 5 will have their cubes in the interval 1 to 200. There are such 5 positive numbers (1,2,3,4,5).
To calculate the variety of integers, locate and subtract the integers of the hobby after which subtract 1. As evidence of the concept, calculate the wide variety of integers that fall between five and 10 on more than a few lines. We realize there are four (6, 7, 8, 9).
All entire numbers are integers (and all herbal numbers are integers), however now not all integers are whole numbers or natural numbers. as an example, -five is an integer but not an entire variety or a natural quantity. An integer is an entire variety (not a fractional number) that can be fine, bad, or 0. Examples of integers are: -5, 1, 5, 8, 97, and 3,043. Examples of numbers that are not integers are: -1.forty three, 1 3/four, three.14, . 09, and five,643.1.
Learn more about integers here: brainly.com/question/17695139
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