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4 years ago

Sarah and four friends are decorating picture frames with ribbon. They have 4 rollsof ribbon to share evenly?

1 answer:

7 0

"Sarah and four friends", this means that we have a total of 5 persons.
They have four rolls of ribbon to share evenly.
1- This represents division as they have to equally divide four rolls among them.

2- The share of each can be calculated by dividing the four rolls they have by the five of them as follows:
share of each = 4/5 rolls = 0.8 rolls

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Olga had more than 6 aces in what percent of tennis matches

Tanya [424]

Answer:

50%

Step-by-step explanation:

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5 0

3 years ago

A quiz consists of 20 multiple-choice questions find mean and standard deviation

worty [1.4K]

Since the problem is quite vague because the number of choice per question is not written here. I’ll just put for 4 choices and 5 choices each.

To compute for the 5 choices each:

Mean = np = 20 (1/5) = 4

Standard deviation = sqrt(npq) = sqrt (4*(4/5) = 1.79

To compute for the 4 choices each:

Mean = np = 20 (1/4) = 5

Standard deviation = sqrt(npq) = sqrt (5*(4/5) = 2

4 0

3 years ago

I don't understand this question.

OlgaM077 [116]

X - y > 2 at (5, 4)
5 - 4 > 2
1 > 2

(5, 4) is not a solution to this inequality

3 0

3 years ago

Which of the following is the best thing to do as a first step in using substitution to solve the system of equations? A. Solve

elena-s [515]

The best and most correct answer among the choices provided by the question is the first choice. The first step to do during the substitution method is to s<span>olve the top equation for x. </span><span>I hope my answer has come to your help. God bless and have a nice day ahead!</span>

5 0

3 years ago

In a certain computer, the probability of a memory failure is 0.01, while the probability of a hard disk failure is 0.02. If the

ratelena [41]

Answer:

We need to remember that we have independent events when a given event is not affected by previous events, and we can verify if two events are independnet with the following equation:

$P(A \cap B) = P(A) *P(B)$

For this case we have that:

$P(A) *P(B) = 0.01*0.02= 0.0002$

And we see that $0.0002 \neq P(A \cap B)$

So then we can conclude that the two events given are not independent and have a relationship or dependence.

Step-by-step explanation:

For this case we can define the following events:

A= In a certain computer a memory failure

B= In a certain computer a hard disk failure

We have the probability for the two events given on this case:

$P(A) = 0.01 , P(B) = 0.02$

We also know the probability that the memory and the hard drive fail simultaneously given by:

$P(A \cap B) = 0.0014$

And we want to check if the two events are independent.

We need to remember that we have independent events when a given event is not affected by previous events, and we can verify if two events are independnet with the following equation:

$P(A \cap B) = P(A) *P(B)$

For this case we have that:

$P(A) *P(B) = 0.01*0.02= 0.0002$

And we see that $0.0002 \neq P(A \cap B)$

So then we can conclude that the two events given are not independent and have a relationship or dependence.

8 0

3 years ago