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Likurg_2 [28]
3 years ago
15

Sarah and four friends are decorating picture frames with ribbon. They have 4 rollsof ribbon to share evenly?

Mathematics
1 answer:
ki77a [65]3 years ago
7 0
"Sarah and four friends", this means that we have a total of 5 persons.
They have four rolls of ribbon to share evenly.
1- This represents division as they have to equally divide four rolls among them.

2- The share of each can be calculated by dividing the four rolls they have by the five of them as follows:
share of each = 4/5 rolls = 0.8 rolls


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Step-by-step explanation:

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2 years ago
An airplane is preparing to land at an airport. It is 44,8000 feet above the ground and is descending at the rate of 3,100 feet
Marina86 [1]

Answer:

Time: 8 minutes

Altitude: 20000ft

Method 1 is easiest

Method 3 is easiest

Step-by-step explanation:

Given

Airplane 1:

Height = 44800 ft

Descending\ Rate = 3100ft/min

Airplane 2:

Ascending\ Rate = 2500ft/min

Required

Determine when both planes would be at the same altitude?

Let the minute be represented by m

For Airplane 1, Its altitude at any height h is:

Airplane\ 1 = Height - Descending\ Rate * m

<em>It is minus (-) because the airplane is descending</em>

Airplane\ 1 = 44800 - 3100 * m

Airplane\ 1 = 44800 - 3100m

For Airplane 2, Its altitude at any height h is:

Airplane\ 2 = Ascending\ Rate * m

Airplane\ 2 = 2500 * m

Airplane\ 2 = 2500m

Method 1:

For both heights to be equal, we have that:

Airplane\ 1 = Airplane\ 2

This gives:

44800 - 3100m = 2500m

Collect Like Terms

44800 = 2500m + 3100m

44800 = 5600m

5600m = 44800

m = 44800/5600

m = 8\ min

<em>Hence, the time they will be at the same altitude is 8 minutes</em>

Substitute 8 for m in

Airplane\ 2 = 2500m

Airplane\ 2 = 2500 * 8

Airplane\ 2 = 20000\ ft

<em>Hence, they will be at the same altitude at 20000ft</em>

Method 2:

We have that:

Airplane\ 1 = 44800 - 3100m

Airplane\ 2 = 2500m

Since they are to be at the same altitude, then

The difference in their altitude must be 0

i.e.

Airplane\ 1 - Airplane\ 2 = 0

This gives

44800 - 3100m - 2500m = 0

44800 - 5600m = 0

Collect Like Terms

5600m = 44800

m = 44800/5600

m = 8\ min

Substitute 8 for m in

Airplane\ 1 = 44800 - 3100m

Airplane\ 1 = 44800 - 3100 * 8

Airplane\ 1 = 44800 - 24800

Airplane\ 1 = 20000\ ft

Method 3:

We have that:

Airplane\ 1 = 44800 - 3100m

Airplane\ 2 = 2500m

Since they are to be at the same altitude, then

The ratio of their altitudes must be 1

i.e.

\frac{Airplane\ 1}{Airplane\ 2} = 1

\frac{44800 - 3100m}{2500m} = 1

Cross Multiply

44800 - 3100m = 1 * 2500m

44800 - 3100m = 2500m

Collect Like Terms

44800 = 2500m + 3100m

44800 = 5600m

5600m = 44800

m = 44800/5600

m = 8\ min

Substitute 8 for m in

Airplane\ 1 = 44800 - 3100m

Airplane\ 1 = 44800 - 3100 * 8

Airplane\ 1 = 44800 - 24800

Airplane\ 1 = 20000\ ft

Hence;

<em>Their altitudes must be 20000ft</em>

<em>Though the three methods applied uses the same logic at some point, the first method applied is still the easiest and it is a straight forward method that could be applied in solving the question.</em>

<em>Method 3 is the most difficult.</em>

7 0
3 years ago
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