The question here is how long does it take for a falling
person to reach the 90% of this terminal velocity. The computation is:
The terminal velocity vt fulfills v'=0. Therefore vt=g/c,
and so c=g/vt = 10/(100*1000/3600) = 36,000/100,000... /s. Incorporating the
differential equation shows that the time needed to reach velocity v is
t= ln [g / (g-c*v)] / c.
With v=.9 vt =.9 g/c,
t = ln [10] /c = 6.4 sec.
Answer:
16 students can sit around a cluster of 7 square table.
Step-by-step explanation:
Consider the provided information.
We need to find how many students can sit around a cluster of 7 square table.
The tables in a classroom have square tops.
Four students can comfortably sit at each table with ample working space.
If we put the tables together in cluster it will look as shown in figure.
From the pattern we can observe that:
Number of square table in each cluster Total number of students
1 4
2 6
3 8
4 10
5 12
6 14
7 16
Hence, 16 students can sit around a cluster of 7 square table.
I don’t know how to explain but I can work out the correct ans
To find how much is needed for one person
280/4=70
For 10 person:70*10=700
You are given a table in which each row represents the coordinates of points. For example, in the first line, we have x=-7 and y=5. Work through the four given equations, one at a time, subbing -7 for x and 5 for y; is the equation still true? If yes, then you have found the correct answer. B is the exception; I'd suggest you check out equations A, C and D first, before focusing on B.
Example: D: (5)-5 = 2((-7) + 7) leads to 0 = 0. Is that true? If so, D is likely the correct answer.
