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MatroZZZ [7]
3 years ago
8

Solve the following equation. Then place the correct number in the box provided.

Mathematics
2 answers:
raketka [301]3 years ago
7 0

The answer is:

z ≥ − 6

melisa1 [442]3 years ago
4 0

Your answer should be z ≥ − 6


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Find the limit as x approaches 0 for cos(2x) / x
zhenek [66]

We are asked to determine the limits of the function cos(2x) / x as x approaches to zero. In this case, we first substitute zero to x resulting to 1/0.  A number, any number divided by zero is always equal to infinity, Hence there are no limits to this function.
5 0
3 years ago
Pleaseee helppppppppppp
Greeley [361]

Answer:

The y-value (output) is equal to 1

Step-by-step explanation:

f(x) = 1

f(x) takes the place of y, so this could be rewritten as

y = 1

3 0
3 years ago
The perimeter of a rectangle is 72 in. The base is 3 times the height. Find the area of the rectangle
Dovator [93]

Answer:

243 in²

Step-by-step explanation:

Step 1. Calculate the<em> base and height </em>of the rectangle

We have two conditions:

(1)   2b+ 2h = 72 in

(2)           b = 3h               Substitute in (1)

2(3h) + 2h = 72               Remove parentheses

   6h + 2h = 72               Combine like terms

           8h = 72               Divide by 6

             h = 9 in             Substitute in(2)

             b = 3 × 9

             b = 27 in

Step 2. Calculate the area of the rectangle

A = bh

A = 27 × 9

A = 243 in²

The area of the rectangle is 243 in².

7 0
3 years ago
Halley's birthday is on Friday. On Monday she receives 23 birthday cards. On Tuesday she receives 5 birthday cards. On Wednesday
Deffense [45]

Answer:

80

Step-by-step explanation:

17+13=30

22+23+5=50

30+50=80

6 0
3 years ago
Anyone good with algebra 2??
sweet [91]
A discontinuity is a point that cannot exist because the x-coordinate would cause a problem in the equation. If you have a polynomial in the denominator, you must find which values of x would cause the polynomial in the denominator to evaluate to zero. Since division by zero is undefined, that would cause a discontinuity.

Let's look at your function.

f(x) = \dfrac{x^2 - 16}{6x - 24}

x^2 - 16  is in the numerator. It is defined for every value of x. There is no problem there.

6x - 24  is in the denominator. This is a function defined for every value of x, but since it is in the denominator, we must exclude the x-value that would cause this polynomial to evaluate to zero.

We set it equal to zero and solve the equation for x.

6x - 24 = 0

6x = 24

x = 4

For x = 0, the denominator has a value of zero, so at this point there is a discontinuity in function f(x).

The answer is:

x \ne 4

6 0
3 years ago
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