Answer:
KI=11.25 and HI=6.75
Step-by-step explanation:
Consider the below figure attached with this question.
According to Pythagoras Theorem:
![base^2+perpendicular^2=hypotenuse^2](https://tex.z-dn.net/?f=base%5E2%2Bperpendicular%5E2%3Dhypotenuse%5E2)
Use Pythagoras in triangle HKL
![LH^2+KH^2=LK^2](https://tex.z-dn.net/?f=LH%5E2%2BKH%5E2%3DLK%5E2)
![(LH)^2+9^2=15^2](https://tex.z-dn.net/?f=%28LH%29%5E2%2B9%5E2%3D15%5E2)
![(LH)^2+81=225](https://tex.z-dn.net/?f=%28LH%29%5E2%2B81%3D225)
![(LH)^2=144](https://tex.z-dn.net/?f=%28LH%29%5E2%3D144)
Taking square root on both sides.
![LH=12](https://tex.z-dn.net/?f=LH%3D12)
Let length of HI be x.
LI = 12+x
Use Pythagoras theorem in ΔKLI,
![(KI)^2+15^2=(12+x)^2](https://tex.z-dn.net/?f=%28KI%29%5E2%2B15%5E2%3D%2812%2Bx%29%5E2)
![(KI)^2+225=x^2+24x+144](https://tex.z-dn.net/?f=%28KI%29%5E2%2B225%3Dx%5E2%2B24x%2B144)
![(KI)^2=x^2+24x+144-225](https://tex.z-dn.net/?f=%28KI%29%5E2%3Dx%5E2%2B24x%2B144-225)
![(KI)^2=x^2+24x-81...(1)](https://tex.z-dn.net/?f=%28KI%29%5E2%3Dx%5E2%2B24x-81...%281%29)
Use Pythagoras theorem in ΔHKI,
![(KI)^2=x^2+9^2](https://tex.z-dn.net/?f=%28KI%29%5E2%3Dx%5E2%2B9%5E2)
![(KI)^2=x^2+81...(2)](https://tex.z-dn.net/?f=%28KI%29%5E2%3Dx%5E2%2B81...%282%29)
From (1) and (2) we get
![x^2+81=x^2+24x-81](https://tex.z-dn.net/?f=x%5E2%2B81%3Dx%5E2%2B24x-81)
![24x=162](https://tex.z-dn.net/?f=24x%3D162)
![x=\dfrac{162}{24}=6.75](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B162%7D%7B24%7D%3D6.75)
Hence, the measure of HI is 6.75 units.
Substitute x=6.75 in equation (2).
![(KI)^2=(6.75)^2+81](https://tex.z-dn.net/?f=%28KI%29%5E2%3D%286.75%29%5E2%2B81)
![(KI)^2=126.5625](https://tex.z-dn.net/?f=%28KI%29%5E2%3D126.5625)
Taking square root on both sides.
![KI=\sqrt{126.5625}](https://tex.z-dn.net/?f=KI%3D%5Csqrt%7B126.5625%7D)
![KI=11.25](https://tex.z-dn.net/?f=KI%3D11.25)
Hence, the measure of KI is 11.25 units.
The answer is that there is a proximity 10 miles of coast 9.904... it be exact
Answer:
x=5/2, y=-3/2. (5/2, -3/2).
Step-by-step explanation:
2=2y+5
3y-3x=-12
--------------
2-5=2y
2y=-3
y=-3/2
3(-3/2)-3x=-12
-9/2-3x=-12
3x=-9/2-(-12)
3x=-9/2+12
3x=-9/2+24/2
3x=15/2
x=(15/2)/3
x=(15/2)(1/3)
x=15/6=5/2
Total of 90 fish:
c + p = 90
Charlie gave 1/4 c to Peter. Now
Charlie has c - (1/4) c
Peter has p + (1/4) c
Peter gave 2/5 of his to Charlie. Now
Peter has p + (1/4) c - 2/5( p + (1/4) c )
Charlie has c - (1/4) c + 2/5( p + (1/4) c )
And then they had equal number:
c - (1/4) c + 2/5( p + (1/4) c ) = p + (1/4) c - 2/5( p + (1/4) c )
Let's do the easy subtractions then multiply by 20 to clear the fractions,
(3/4) c + 2/5( p + (1/4) c ) = 3/5( p + (1/4) c )
15c + 8p + 2c = 12p + 3c
14c = 4p
7c = 2p
c + p = 90
2c + 2p = 180
2c + 7c = 180
9c = 180
c = 20
p = 70
Answer: Charlie started with 20, Peter with 70
Check:
Initially C:20, P:70
1/4(20)=5 to P
C:15, P:75
(2/5) 75 = 30 to C
C:45, P45
Good
Answer:
Option C, ![f(-1) = 4\\](https://tex.z-dn.net/?f=f%28-1%29%20%3D%204%5C%5C)
Step-by-step explanation:
<u>Step 1: Set x to -1</u>
<u />![f(x)=4x^2](https://tex.z-dn.net/?f=f%28x%29%3D4x%5E2)
![f(-1)=4(-1)^2](https://tex.z-dn.net/?f=f%28-1%29%3D4%28-1%29%5E2)
![f(-1)= 4(1)](https://tex.z-dn.net/?f=f%28-1%29%3D%204%281%29)
![f(-1) = 4\\](https://tex.z-dn.net/?f=f%28-1%29%20%3D%204%5C%5C)
Answer: Option C, ![f(-1) = 4\\](https://tex.z-dn.net/?f=f%28-1%29%20%3D%204%5C%5C)