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3 years ago

The number 1.3,1/1/3,1.34 in least to greatest

1 answer:

4 0

1.3, 1 1/3, 1.34

The decimal version of 1 1/3 is 1.333 (so on)

so 1.3 is less than 1.333 and 1.333 is less than 1.34

1.3<1.333<1.34

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M=7n make n the subject

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We divide both sides by 7 which makes n alone. Which is n=m/7.

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3 years ago

What is the value of x?

gulaghasi [49]

I believe the answer is X=15

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3 years ago

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A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he

mojhsa [17]

Answer:

(A) The minimum sample size required achieve the margin of error of 0.04 is 601.

(B) The minimum sample size required achieve a margin of error of 0.02 is 2401.

Step-by-step explanation:

Let us assume that the percentage of support for the candidate, among voters in her district, is 50%.

(A)

The margin of error, MOE = 0.04.

The formula for margin of error is:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}$

The critical value of z for 95% confidence interval is: $z_{\alpha/2}=1.96$

Compute the minimum sample size required as follows:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.04=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.04}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=600.25\approx 601$

Thus, the minimum sample size required achieve the margin of error of 0.04 is 601.

(B)

The margin of error, MOE = 0.02.

The formula for margin of error is:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}$

The critical value of z for 95% confidence interval is: $z_{\alpha/2}=1.96$

Compute the minimum sample size required as follows:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.02=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.02}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=2401.00\approx 2401$

Thus, the minimum sample size required achieve a margin of error of 0.02 is 2401.

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3 years ago

Item 12

zlopas [31]

Answer: about 14pi inches

Explanation:

7 * 6.28319 = 43.9823

43.9823 / 3.14159 = 14.0000127324

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3 years ago

What are the solutions of the system?

siniylev [52]

$y=x^2-3x+2 \\y=4x-4$

A. (1, 0) and (–6, –28)

B. (1, 20) and (6, 0)

C. (1, 0) and (6, 20)

D. no solution

Correct answer is C.

$y=x^2-3x+2 \\y=4x-4\\ \\4x-4=x^2-3x+2 \\x^2-7x+6=0 \\x^2-6x-x+6=0 \\x(x-6)-(x-6)=0 \\(x-6)(x-1)=0 \\x=6\,\text{ or }x=1 \\y=4\times 6-4=20 \,\text{ or }y=4\times 1-4=0 \\ \\(6,20)\,\text{ and }(1,0)$

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3 years ago

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