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vova2212 [387]
4 years ago
6

Writing an Equation with a Given Center and Radius

Mathematics
1 answer:
solong [7]4 years ago
4 0

Answer:

(x-2)^2+(y+8)^2=121

Step-by-step explanation:

A circle is described by an equation in the following form:

(x-x_0)^2 + (y-y_0)^2 = r^2 (1)

where:

x_0 is the x-coordinate of the centre of the circle

y_0 is the y-coordinate of the centre of the circle

r is the radius of the circle

For the circle in this problem, we have:

- The centre is located at (2,-8), so

x_0=2\\y_0 = -8

- The radius is 11, so

r=11

Therefore substituting into eq(1) we find the equation of this circle:

(x-2)^2+(y+8)^2=11^2 = 121

So the correct option is option B:

(x-2)^2+(y+8)^2=121

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