Question

Writing an Equation with a Given Center and Radius

Answer 1

Answer:

$(x-2)^2+(y+8)^2=121$

Step-by-step explanation:

A circle is described by an equation in the following form:

$(x-x_0)^2 + (y-y_0)^2 = r^2$ (1)

where:

$x_0$ is the x-coordinate of the centre of the circle

$y_0$ is the y-coordinate of the centre of the circle

r is the radius of the circle

For the circle in this problem, we have:

- The centre is located at (2,-8), so

$x_0=2\\y_0 = -8$

- The radius is 11, so

$r=11$

Therefore substituting into eq(1) we find the equation of this circle:

$(x-2)^2+(y+8)^2=11^2 = 121$

So the correct option is option B:

$(x-2)^2+(y+8)^2=121$