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GenaCL600 [577]
3 years ago
12

How do I solve (5y-29) = (3y+19)

Mathematics
2 answers:
tekilochka [14]3 years ago
8 0
Simplifying
5y + -29 = 3y + 19

Reorder the terms:
-29 + 5y = 3y + 19

Reorder the terms:
-29 + 5y = 19 + 3y

Solving
-29 + 5y = 19 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
-29 + 5y + -3y = 19 + 3y + -3y

Combine like terms: 5y + -3y = 2y
-29 + 2y = 19 + 3y + -3y

Combine like terms: 3y + -3y = 0
-29 + 2y = 19 + 0
-29 + 2y = 19

Add '29' to each side of the equation.
-29 + 29 + 2y = 19 + 29

Combine like terms: -29 + 29 = 0
0 + 2y = 19 + 29
2y = 19 + 29

Combine like terms: 19 + 29 = 48
2y = 48

Divide each side by '2'.
y = 24

Simplifying
y = 24
leonid [27]3 years ago
4 0
Answer: y = 24

(5y - 29) = (3y + 19)                       Distributive Property
5y - 29 = 3y + 19                           Subtract 3y from both sides
2y - 29 = 19                                   Add 29 to both sides
2y = 48                                          Divide by 2 to both sides
y = 24                                            Answer!
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Step-by-step explanation:

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Mr. Chan places $4000 in a bank as a fixed deposit for 2 years. The bank offers an interest compounded yearly. At the end of 2 y
serious [3.7K]

Answer:

Step-by-step explanation:

Mr. Chan originally placed 4,000 in the bank as a fixed deposit for 2 years.

Each years the bank added a certain amount of interest.

At the end of the 2 years he gained 243 dollars and 60 cents just from interest.

How to solve:

Simply take away the 4 in the amount of money

Leaving: $243.60

( 2 years )

Now divide 243.60 by 1/2

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3 years ago
What is the equation of the line that passes through the points (4/5,1/5) and (1/2,3/2)?​
Setler [38]

Answer:

y-\frac{3}{2}=\frac{-13}{3}(x-\frac{1}{2}) point-slope form

13x+3y=11 (standard form)

Let me know if you prefer another form.

Step-by-step explanation:

The slope of a line can be found using \frac{y_2-y_1}{x_2-x_1} provided you are given two points on the line.

We are.

Now you can use that formula.  But I really love to just line up the points vertically then subtract them vertically then put 2nd difference over 1st difference.

 (4/5  ,  1/5)

-( 1/2  ,  3/2)

-----------------

3/10          -13/10

2nd/1st = \frac{\frac{-13}{10}}{\frac{3}{10}}=\frac{-13}{3} is our slope.

So the following is point-slope form for a linear equaiton:

y-y_1=m(x-x_1) \text{ where } m \text{ is slope and } (x_1,y_1) \text{ is a point on the line }    

Plug in a point (x_1,y_1)=(\frac{1}{2},\frac{3}{2}) \text{ and } m=\frac{-13}{3}.

This gives:

y-\frac{3}{2}=\frac{-13}{3}(x-\frac{1}{2})

I'm going to distribute:

y-\frac{3}{2}=\frac{-13}{3}x-\frac{-13}{6}

Now I don't like these fractions so I'm going to multiply both sides by the least common multiply of 2,3, and 6 which is 6:

6y-9=-26x+13

Add 26x on both sides:

26x+6y-9=13

Add 9 on both sides:

26x+6y=22 This is actually standard form of a line.

It can be simplified though.

Divide both sides by 2:

13x+3y=11 (standard form)

7 0
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