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denis23 [38]
4 years ago
7

The length of a rectangle is 4 units greater than its width, and the area of the rectangle can be expressed by the equation y=xs

quared +4x. What is a resonable domain for this function?
Mathematics
2 answers:
Delicious77 [7]4 years ago
5 0
X>0 and y>0 therefore, (0,≈)
Firlakuza [10]4 years ago
3 0

Answer:

The domain of the function is D=x|x>0

Step-by-step explanation:

Given : The length of a rectangle is 4 units greater than its width, and the area of the rectangle can be expressed by the equation y=x^2+4x

To find : What is a reasonable domain for this function?

Solution :

Domain is defined as the all possible set of values in which function is defined.

We have given the area,

y=x^2+4x

We know, Area will never be negative so the value of x is always positive.

So, y> 0

x^2+4x>0

x(x+4)> 0

i.e. Either x>0

or x+4> 0

x> -4 but x>0

So, The value of x is defined from 0 to infinity.

The domain of the function is D=x|x>0

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0    0.029         0              0                0

1     0.147        0.147           1              0.147

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The mean of the random variable is

\mu=\sum xP(x)=2.5

The standard deviation of the random sample is

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\sigma^2=\sum x^2P(x)-\mu^2

\sigma^2=7.436-(2.5)^2

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\sigma^2=1.186

\sigma=\sqrt{1.186}

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Therefore, The mean is 2.5 and the standard deviation is 1.08.

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